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vazorg [7]
3 years ago
8

A bag of marbles is hanging motionless on a spring scale. What prevents the bag from falling?​

Physics
1 answer:
Tanya [424]3 years ago
7 0

Answer:

The vector sum of all forces acting on it is zero, its at equilibrium.

Explanation:

The bag of marbles hanging on a spring scale applies its weight downwards, which was counterbalanced by the reaction from the spring scale (obeying the Newton's third law of motion). And since no external forces are applied to the system, thus the equilibrium of the system.

If the weight of the bag is greater than the reaction from the spring scale, the scale breaks and the system would not be balanced.

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Two small conducting point charges, separated by 0.4 m, carry a total charge of 200 C. They repel one another with a force of 12
Lunna [17]

Answer:

200 C

Explanation:

Let C1 and C2 be their charges. According to Coulomb's law

F_C = k\frac{C_1C_2}{R^2}

where k = 8.99\times10^9 nm^2/C^2 is the constant, R = 0.4m is the distance between them, F = 120 N is their resulting charge force

120 = 8.99\times10^9\frac{C_1C_2}{0.4^2}

C_1C_2 = \frac{120*0.4^2}{8.99\times10^9} = 2.13\times10^{-9}

Since their total charge is 200C:

C_1 + C_2 = 200 or C_1 = 200 - C_2

We can substitute the above equation

C_1C_2 = (200 - C_2)C_2 = 2.13\times10^{-9}

-C_2^2 +200C_2 - 2.13\times10^{-9} = 0

C= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

C= \frac{-200\pm \sqrt{(200)^2 - 4*(-1)*(-0.00000000213)}}{2*(-1)}

C= \frac{-200\pm200}{-2}

C = 1.06 \times 10^{-11} or C \approx 200

So the larger charge is C = 200 C

8 0
3 years ago
A pendulum is made by attaching a sphere to the end of a string of negligible mass and it oscillates when released from an angle
Rudik [331]

Answer:

Angular momentum conservation and kinetic energy. Torsional ... motion-observation of what a given object does in relation to other objects. Frames of ... shows that the rectangular and spherical polar coordinates are related as follows: ... 2mo, which are connected by a string over a pulley of negligible mass and prevented.

Explanation:

8 0
3 years ago
A plane flies from base camp to lake a, 200 km away in the direction 20.0° north of east. after dropping off supplies it flies t
Liono4ka [1.6K]

Distance of lake a is 200 km at 20 degree north of east

distance between lake a and b is 230 km at 30 degree west of north

now the distance between base and lake b is given as

d = d_1 + d_2

given that

d_1 = 200 cos20 i + 200 sin20 j

d_1 = 187.94 i + 68.4 j

d_2 = -230 sin30 i + 230 cos30 j

d_2 = -115 i + 199.2 j

now the total distance is

d = (187.94 - 115)i + (199.2 + 68.4)j

d = 72.94 i + 267.6 j

now the magnitude of the distance is given as

d = \sqrt{72.94^2 + 267.6^2}

d = 277.4

also the direction is given as

\theta = tan^{-1}\frac{267.6}{72.94}

\theta = 74.7 degree

<em>so it is 277.4 km at 74.7 degree North of East</em>

8 0
3 years ago
Which energy conversion takes place when a solar cell is used to light a street lamp?
allsm [11]

Answer:

the answer is for the question is B

8 0
2 years ago
The Displacement is 5m. We found that using the
Llana [10]

Answer:

A vector can be written as:

(R, θ)

Where R is the magnitude, in this case, we know that the magnitude of the displacement is 5m

Then:

R = 5m

and θ defines the direction, it's an angle measured from the positive x-axis.

(In the image, θ would be the angle located at the point A)

Now, if you look at the image, you can see a triangle rectangle.

Where the adjacent cathetus has a length of 4,

the opposite cathetus has a length of 3 units

the hypotenuse has a length of 5 units.

So we can use any trigonometric rule to find the value of θ, like:

sin(θ) = (opposite cathetus)/hypotenuse

Then:

sin(θ) = 3m/5m

Now we can use the inverse sin function, Asin(x), in both sides

Asin( sin(θ)) = θ = Asin( 3/5) = 36.87°

then the vector is:

(5m, 36.87°)

Now, if we define the positive y-axis as the North, and the positive x-axis as the East.

This vector would point at 36.87° North of East.

(or almost Northeast)

7 0
2 years ago
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