Answer:
The current through the tube is 73.39A.
Explanation:
The relationship between the resistivity
, the electric field
, and the current density
is given by
![\rho = \dfrac{E}{J}](https://tex.z-dn.net/?f=%5Crho%20%3D%20%5Cdfrac%7BE%7D%7BJ%7D)
This equation can be solved for
to get:
![J = \dfrac{E}{\rho}](https://tex.z-dn.net/?f=J%20%3D%20%5Cdfrac%7BE%7D%7B%5Crho%7D)
Since the current is ![I = J\cdot A](https://tex.z-dn.net/?f=I%20%3D%20J%5Ccdot%20A)
![I= J\cdot A = \dfrac{E}{\rho} \cdot A](https://tex.z-dn.net/?f=I%3D%20J%5Ccdot%20A%20%20%3D%20%5Cdfrac%7BE%7D%7B%5Crho%7D%20%5Ccdot%20A)
Now, for the tube of mercury
,
, and the area is
; therefore,
![I= \dfrac{23N/C}{9.84*10^{-7}\Omega\cdot m } *3.14*10^{-6}m^2](https://tex.z-dn.net/?f=I%3D%20%5Cdfrac%7B23N%2FC%7D%7B9.84%2A10%5E%7B-7%7D%5COmega%5Ccdot%20m%20%7D%20%2A3.14%2A10%5E%7B-6%7Dm%5E2)
![\boxed{I = 73.39A.}](https://tex.z-dn.net/?f=%5Cboxed%7BI%20%3D%2073.39A.%7D)
Hence, the current through the mercury tube is 73.39A.
Answer:
Question 1: D
Question 2:D
Explanation:
Question 1: D
Question 2
mass=m=65kg
Acceleration due to gravity=g=9.8m/s^2
Height=h=7 meters
Potential energy=m x g x h
Potential energy=65 x 9.8 x 7
Potential energy=4459 joules
By definition,
Momentum = Mass x Velocity.
For mouse of mass, m, and velocity components (Vx, Vy),
the components of momentum are
px = m*Vx
py = m*Vy
Construct a table to display m, Vx, Vy, px, and py as shown below.
m, kg Vx, m/s Vy, m/s px, (kg-m)/s py (kg-m)/s
---------- ---------- ---------- ----------------- ----------------
0.0227 0.517 -0.493 0.0117 -0.0112
0.0217 -0.603 -0.309 -0.0131 -0.0067
0.0215 0.373 0.477 0.0080 0.0103
0.0235 -0.853 0.955 -0.0200 0.0224
Answer:
The distance between the crest will decrease as the frequency of the waves increase.
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