1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vazorg [7]
3 years ago
8

A bag of marbles is hanging motionless on a spring scale. What prevents the bag from falling?​

Physics
1 answer:
Tanya [424]3 years ago
7 0

Answer:

The vector sum of all forces acting on it is zero, its at equilibrium.

Explanation:

The bag of marbles hanging on a spring scale applies its weight downwards, which was counterbalanced by the reaction from the spring scale (obeying the Newton's third law of motion). And since no external forces are applied to the system, thus the equilibrium of the system.

If the weight of the bag is greater than the reaction from the spring scale, the scale breaks and the system would not be balanced.

You might be interested in
A projectile is launched at an angle into the air at velocity v and angle θ. Determine its vertical acceleration.
Vesna [10]

g = t.u \sin(?)
5 0
4 years ago
What is the frequency of a radio wave with an energy of 3.686 × 10−24 j/photon?answer in units of hz?
Makovka662 [10]

To solve this problem, we have to use the formula:

E = h f

where E is total energy, h is Plancks constant 6.626x10^-34 J s, f is frequency

 

f = E / h

f = 3.686 × 10−24 J / (6.626x10^-34 J s)

<span>f = 5.56 x 10^9 Hz</span>

4 0
3 years ago
Energy is the energy an object has because it is in motion. *
Mrrafil [7]

The energy an object has due to its motion is called kinetic energy.

3 0
2 years ago
Determine the kinetic energy of a 55kg woman running with the velocity of 5.87m/s
Greeley [361]
The formula for kinetic energy = ½m·v<span>2

1/2 * 55 kg x 5,87 m/s ^2 = 27.5 x </span>34.4569 = <span>947.56475 Joule </span>≈ 948 J
4 0
3 years ago
You drag a crate across a floor with a rope. The force applied is 750 N and the angle of the rope is 25.0° above the horizontalH
frez [133]

a.

The work done by a constant force along a rectilinear motion when the force and the displacement vector are not colinear is given by:

W=F\cos\theta\cdot d

where F is the magnitude of the force, theta is the angle between them and d is the distance.

The problen gives the following data:

The magnitude of the force 750 N.

The angle between the force and the displacement which is 25°

The distance, 26 m.

Plugging this in the formula we have:

\begin{gathered} W=\left(750\right)\left(\cos25\right)\left(26\right) \\ W=17673 \end{gathered}

Therefore the work done is 17673 J.

b)

The power is given by:

P=\frac{W}{t}

the problem states that the time it takes is 6 s. Then:

\begin{gathered} P=\frac{17673}{6} \\ P=2945.5 \end{gathered}

Therefore the power is 2945.5 W

5 0
1 year ago
Other questions:
  • A ball rolling across the floor at a velocity of 6.15 m/s [E] slows to rest in 1.00 minute. The
    6·1 answer
  • A 15kg penguin slips on a wet rock (rip I hope he's okay). The coefficient of friction between the penguin and the rock is .250.
    10·1 answer
  • A stick is resting on a concrete step with 2/5 of its length hanging over the edge. A single ladybug lands on the end of the sti
    12·1 answer
  • Most people can hear sound of pitch raning from to hertz​
    12·1 answer
  • What kind of energy do u use for cooking and heating
    8·2 answers
  • Find the change in internal energy, AU, if Q = 2.5 Joules and W = -30.5<br> Joules. *
    7·1 answer
  • Refraction or the bending of waves takes place when a light wave changes A) color. B) frequency. C) intensity. D) speed.
    7·2 answers
  • What is a atomic nuclues
    5·2 answers
  • As the car falls off the cliff, what is happening to the kinetic energy of the falling car?
    12·1 answer
  • In which case would electrical potential energy be built up and stored in the electric field?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!