2Al + 3Cl₂ → 2AlCl₃
mol Al = 2/3 x 1.25 = 0.83
mass Al = 0.83 x 27 g/mol = 22.41 g
Answer:
The differemt isotopes that differ in atomic mass
Explanation:
If 30 grams of KCl is dissolved at 10°C, 14 g of KCl should be added to make a saturated solution at 60 °C.
<h3>What is a saturated solution?</h3>
A saturated solution is a solution in which there is so much solute that if there was any more, it would not dissolve. Its concentration is the same as the solubility at that temperature.
- Step 1. Calculate the mass of water.
At 10 °C, the solubility is 31.2 g KCl/100 g H₂O.
30 g KCl × 100 g H₂O/31.2 g KCl = 96 g H₂O
- Step 2. Calculate the mass of KCl required to prepare a saturated solution at 60 °C.
At 60 °C, the solubility is 45.8 g KCl/100 g H₂O.
96 g H₂O × 45.8 g KCl/100 g H₂O = 44 g KCl
- Step 3. Calculate the mass of KCl that must be added.
44 g - 30 g = 14 g
If 30 grams of KCl is dissolved at 10°C, 14 g of KCl should be added to make a saturated solution at 60 °C.
Learn more about saturated solutions here: brainly.com/question/24564260
Answer:
In 70s we were not much familiar with coca cola. Pepsi were sold in liter and milk is traditionally sold locally sold in gallon.
Explanation:
Sarah Brew said that unlike to the global brand like coca cola, Pepsi are sold at global level but milk is sold at local level follow the local custom measurement. If we look back in history, the milkman sold milk door to door in the form of quartz and the gallons. Same things consumers expected from seller.
These are two ways that play a role in grocery shopping. That's why the congress make a product list in form of liter and metric and traditional inches , gallons, pounds, milk etc.
Answer:
the mass of CaO present at equilibrium is, 0.01652g
Explanation:
![K_p = [CO_2]](https://tex.z-dn.net/?f=K_p%20%3D%20%5BCO_2%5D)
= 3.8×10⁻²
Now we have to calculate the moles of CO₂
Using ideal gas equation,
PV =nRT
P = pressure of gas = 3.8×10⁻²
T = temperature of gas = 1000 K
V = volume of gas = 0.638 L
n = number of moles of gas = ?
R = gas constant = 0.0821 L.atm/mole.k
Now we have to calculate the mass of CaO
mass = 2.95 * 10 ⁻⁴ × 56
= 0.01652g
Therefore,
the mass of CaO present at equilibrium is, 0.01652g
