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Svetach [21]
3 years ago
7

When a 5.00-g sample of rbbr is dissolved in water in a calorimeter?

Chemistry
1 answer:
lilavasa [31]3 years ago
7 0
To answer this question, I found a similar problem as shown in the picture below. Let's use the given information: Heat capacity = 3.565 kJ/K, ΔT = 0.26 K. Also, the molar mass of RbBr is 165.372 g/mol.

The solution is as follows:

Molar Heat of Solution = (3.565 kJ/K)(0.26 K)(1/ 5 g)(165.372 g/mol)
<em>Molar Heat of Solution = 30.66 kJ/mol</em>

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Data:

weight of water before heating = 0.349

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Formula:

Weight percent of water = [ (weight of water) / (weight of the hydrate) ] * 100

Solution:

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Answer: 16.6%
3 0
4 years ago
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<h3>What is a mole?</h3>

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Rzqust [24]
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trapecia [35]

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Explanation:

i hope its the right answer

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