The fission reaction released the most energy per amu when compared to the fusion reaction.
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Energy released per amu for Fusion</h3>
The amount of energy released per amu for fusion is given as 0.36 J/amu.
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Energy released per amu for Fission</h3>
The amount of energy released per amu for fission is given as 0.85106383 J/amu.
From the different energy released per amu, it is obvious that 0.85106383 J/amu is greater than 0.36 J/amu.
Thus, the fission reaction released the most energy per amu when compared to the fusion reaction.
Learn more about fusion and fission here: brainly.com/question/11290822
From the periodic table, we can see that:
At ground state, the hydrogen atom has one electron
Based on the electronic configuration, at ground state this electron should be occupying the orbital (1s)
Since (1s) is not one of the choices, therefore, the answer is "none of the above"
Answer:
2.04 x 10²⁴ molecules
Explanation:
Given parameters:
Mass of Be(OH)₂ = 145.5g
To calculate the number of molecules in this mass of Be(OH)₂ we follow the following steps:
>> Calculate the number of moles first using the formula below:
Number of moles = mass/molarmass
Since we have been given the mass, let us derive the molar mass of Be(OH)₂
Atomic mass of Be = 9g
O = 16g
H = 1g
Molar Mass = 9 + 2(16 + 1)
= 9 + 34
= 43g/mol
Number of moles = 145.5/43 = 3.38mol
>>> We know that a mole is the amount of substance that contains Avogadro’s number of particles. The particles can be atoms, molecules, particles etc. Therefore we use the expression below to determine the number of molecules in 3.38mol of Be(OH)₂:
Number of
molecules= number of moles x 6.02 x 10²³
Number of molecules= 3.38 x 6.02 x 10²³
= 20.37 x 10²³ molecules
= 2.04 x 10²⁴ molecules
Answer:
C(s)+CO₂(g)→2CO(g)
Explanation:
Basically you’re adding the compounds until they’re equal on both sides
That answer is 2.12 mol H2O