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4 years ago

14

Two cards are drawn without replacement from a standard deck of 52 cards. What is the probability that both cards are diamonds?

Are these events independent?

2 answers:

White raven [17]4 years ago

7 0

11/52 chance. This is a dependent variable

victus00 [196]4 years ago

5 0

Yes its dependent.

11/52

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Tom has a 500 gallon pool. He is able to drain it at a rate of 15 gallons per minute. if the pool still has 170 gallons of wa

Akimi4 [234]

Answer: 22 minutes

Step-by-step explanation: 500-170 means that he drained 330 gallons of water so 330 divided by 15 gallons a minute so you get 22 so it takes 22 minutes to have 170 gallons left in the pool

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3 years ago

16y=14+9y please answer 23 points

NeTakaya

Answer:

<h2>y = 2</h2>

Step-by-step explanation:

$16y=14+9y\qquad\text{subtract}\ 9y\ \text{from both sides}\\\\16y-9y=14+9y-9y\\\\7y=14\qquad\text{divide both sides by 7}\\\\\dfrac{7y}{7}=\dfrac{14}{7}\\\\y=2$

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3 years ago

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ratelena [41]

Step-by-step explanation:

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3 years ago

Find the third side in simplest radical form:<br> 25

Gre4nikov [31]

Answer:

<h3> $\boxed{ \bold{24}}$ </h3>

Step-by-step explanation:

$\mathsf{given}$

$\mathsf{hypotenuse(h) = 25}$

$\sf{perpendicular (p) = 7}$

$\sf{base(b) = }$ ?

Now, Using Pythagoras theorem

$\sf{{h}^{2} = {p}^{2} + {b}^{2} }$

plug the values

⇒ $\sf{ {25}^{2} = {7}^{2} + {b}^{2} }$

Evaluate the power

⇒ $\sf{625 = 49 + {b}^{2} }$

Swap the sides of the equation

⇒ $\sf{49 + {b}^{2} = 625}$

Move constant to right hand side and change it's sign

⇒ $\sf{ {b}^{2} = 625 - 49}$

Calculate the difference

⇒ $\sf{ {b}^{2} = 576}$

Squaring on both sides

⇒ $\sf{b = 24}$

Hope I helped!

Best regards!

8 0

4 years ago

If \: x + y + z = 0 \: then \: show \: that \: {x}^{3} + {y}^{3 } + {z}^{3} =3xy<br>

tankabanditka [31]

Answer:

Given

x+y+z=0

⟹x+y=−z

Cubing on both sides

(x+y) 3 =(−z) 3

⟹x 3 +y 3 +3x 2y+3xy 2 =−z 3

⟹x 3 +y 3 +3xy(x+y)=−z 3

⟹x 3+y 3+3xy(−z)=−z 3

⟹x 3 +y 3−3xyz=−z 3

⟹x 3 +y 3 +z 3 =3xyz

Step-by-step explanation:

Hope it is helpful.....

8 0

3 years ago