Answer:
work done by electric field is 0.06 J
Explanation:
Given data:
Two point charge is 
0+1 charge positioned is (0 cm , 1 cm, 0.00 cm)
-1 charge positioned is (0 cm , -1 cm, 0.00 cm)
E = 3.0\times 10^6 N/C
From above information, the distance between given two charges d = 2 cm
then d = 0.02m
work needed is W = q E d
W = 0.06 J
Therefore work done by electric field is 0.06 J
Answer:
Explanation:
We have learned that three things are required for the anodic and cathodic steps of corrosion to occur: an electrolyte, an exposed metal surface, and an electron acceptor. It follows, then, that we can prevent corrosion by removing one of these essential conditions.
Answer:
Explanation:
= Energy for defect formation = 1.86 eV
T = Temperature = 
k = Boltzmann constant = 
The fraction of lattice sites that are Schottky defects is given by
The required ratio is .
Answer:
B
Explanation:
The only way the 15mph would fit
