Answer:
The work transfer per unit mass is approximately 149.89 kJ
The heat transfer for an adiabatic process = 0
Explanation:
The given information are;
P₁ = 1 atm
T₁ = 70°F = 294.2611 F
P₂ = 5 atm
γ = 1.5
Therefore, we have for adiabatic system under compression

Therefore, we have;

The p·dV work is given as follows;

Therefore, we have;
Taking air as a diatomic gas, we have;

The molar mass of air = 28.97 g/mol
Therefore, we have

The work done per unit mass of gas is therefore;

The work transfer per unit mass ≈ 149.89 kJ
The heat transfer for an adiabatic process = 0.
Answer:
Ig =7.2 +j9.599
Explanation: Check the attachment
Answer: No
Explanation:
Length= 2cm= 20mm
Now meter stick can read to nearest millimeter.
It is given that length is to be measured with a precision of 1% of 20mm= 1/100 * 20= 0.2mm
Since the least count is 1mm of meter stick and precision required is less than that. So, meter stick cannot be used for this, travelling microscope can be used for this as it can read to 0.1mm.
Answer:
d. is applied after the ceiling joists are
installed.