Answer:
A&C
Step-by-step explanation:
Given:
The figure of a trapezoid.
The figure is translated down 5 units and then rotated 180 degrees clockwise.
To find:
The coordinates of the image of point W after these transformation.
Solution:
From the given figure it is clear that the coordinates of point W are (-6,3).
The figure is translated down 5 units. So,



After that the figure is rotated 180 degrees clockwise.


Therefore, the coordinates of point W after the given transformations are (6,2).
Answer:
1,4
Step-by-step explanation:
2 + 1 is 3. 3 + 4 is 7
3 + 1 is 4. 7 + 4 is 11. so it's 1 up and 4 across
Answer:
Here is the complete question (attachment).
The function which represent the given points are 
Step-by-step explanation:
We know that a general exponential function is like,
We can find the answer by hit and trial method by plugging the values of
coordinates.
Here we are going to solve this with the above general formula.
So as the points are
then for 
Can be arranged in terms of the general equation.
...equation(1) and
...equation(2)

Plugging the values in equation 2.
We have
![\frac{16}{b} b^4=128,16\times b^3=128,b=\sqrt[3]{\frac{128}{16}} =\sqrt[3]{8}=2](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7Bb%7D%20b%5E4%3D128%2C16%5Ctimes%20b%5E3%3D128%2Cb%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B128%7D%7B16%7D%7D%20%3D%5Csqrt%5B3%5D%7B8%7D%3D2)
Plugging
in equation 1.
We have 
Comparing with the general equation of exponential
and 
So the function which depicts the above points =
From theoption we have B as the correct answer.
Answer:
(i) x° = 28°
(ii) y° = 104°
(iii) z° = 76°
Step-by-step explanation:
x° is an alternate interior angle where transversal PQ crosses the parallel lines, so it has the same measure as the one marked 28°.
x° = 28°
__
The base angles of isosceles triangle PQR are both z°, so we must have ...
z° +z° +28° = 180° . . . . . . . . . sum of angles in a triangle
z° = (180° -28°)/2 = 152°/2 . . . solve for z
z° = 76°
__
y° and z° are a linear pair, so ...
y° = 180° -76°
y° = 104°