3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)
From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . . (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)
(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5
From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3
x = 3, y = 0.5, z = -3.5
Answer:
3 minutes
Step-by-step explanation:
d=3t is our formula.
d being the distance (9 inches for this problem)
t is the time in minutes
Substituting our known information would make our equation look like:
9 = 3t
to solve for t we divide both sides of the equation by 3
9/3 = 3t/3
3 = t
So if a snail travels 3 inches per minute, it will have traveled 9 inches in 3 minutes.
Answer:
28/q
Step-by-step explanation:
4 times 7 equals 28 and then divide 28 by q
Answer:
Option C is correct.
Step-by-step explanation:
We are given the expression:

The value of a =5 and k = -2
Putting the values and solving

Option C is correct.