Answer:
hand tracing
Explanation:
as a programmer when we pretend computer in the debugging process by the step of each statement in recording
then there value of variable is hand tracing because as The hand tracking feature is the use of hands as an input method
so while recording value of each variable each step is hand tracing
Answer:
The following statements are true:
A. For flows over a flat plate, in the laminar region, the heat transfer coefficient is decreasing in the flow direction
C. For flows over a flat plate, the transition from laminar to turbulence flow only happens for rough surface
E. In general, turbulence flows have a larger heat transfer coefficient compared to laminar flows 6.
Select ALL statements that are TRUE
B. In the hydrodynamic fully developed region, the mean velocity of the flow becomes constant
D. For internal flows, if Pr>1, the flows become hydrodynamically fully developed before becoming thermally fully developed
Explanation:
In metallurgy, non-ferrous metals are metals or alloys that do not contain iron in appreciable amounts. Generally more costly than ferrous metals, non-ferrous metals are used because of desirable properties such as low weight, higher conductivity, non-magnetic property or resistance to corrosion
Answer:
Engineering Controls. The best engineering controls to prevent heat-related illness is to make the work environment cooler and to reduce manual workload with mechanization. A variety of engineering controls can reduce workers' exposure to heat: Air conditioning, Increased general ventilation
, Cooling fans
, Local exhaust ventilation at points of high heat production or moisture, Reflective shields to redirect radiant heat
, Insulation of hot surfaces Elimination of steam leaks
, Cooled seats or benches for rest breaks
, Use of mechanical equipment to reduce manual work, Misting fans that produce a spray of fine water droplets.
Hope this helped you!
Explanation:
Answer:
The flexural strength of a specimen is = 78.3 M pa
Explanation:
Given data
Height = depth = 5 mm
Width = 10 mm
Length L = 45 mm
Load = 290 N
The flexural strength of a specimen is given by
78.3 M pa
Therefore the flexural strength of a specimen is = 78.3 M pa
