Answer:
A. Antoine Lavoisier
Explanation:
He is know for creating the first chemical textbook. This textbook included rules for naming different chemical compounds, which is the still the same method we use to this day.
Hoped this can help! :D
Answer:
Explanation:
We are given the mass of two reactants, so this is a limiting reactant problem.
We know that we will need mases, moles, and molar masses, so, let's assemble all the data in one place, with molar masses above the formulas and masses below them.
M_r: 17.03 32.00 18.02
4NH₃ + 5O₂ ⟶ 4NO + 6H₂O
m/g: 70.1 70.1
Step 1. Calculate the moles of each reactant
Step 2. Identify the limiting reactant
Calculate the moles of H₂O we can obtain from each reactant.
From NH₃:
The molar ratio of H₂O:NH₃ is 6:4.
From O₂:
The molar ratio of H₂O:O₂ is 6:5.
O₂ is the limiting reactant because it gives the smaller amount of H₂O.
Step 3. Calculate the theoretical yield.
Answer:
1.01 atm
Step-by-step explanation:
To solve this problem, we can use the <em>Combined Gas Laws</em>:
p₁V₁/T₁ = p₂V₂/T₂ Multiply each side by T₂
p₁V₁T₂ = p₂V₂ Divide each side by V₂
p₂ = p₁ × V₁/V₂ × T₂/T₁
Data:
p₁ = 1.05 atm; V₁ = 285 mL; T₁ = 15.8 °C
p₂ = ?; V₂ = 292 mL; T₂ = 11.2 °C
Calculations:
(a) Convert <em>temperatures to kelvins
</em>
T₁ = (15.8+273.15) K = 288.95 K
T₂ = (11.2+273.15) K = 284.35 K
(b) Calculate the <em>pressure
</em>
p₂ = 1.05 atm× (285/292) × (284.35/288.95)
= 1.05 atm × 0.9760 × 0.9840
= 1.01 atm
Answer: D) An Mg atom donates one electron to each of the two Cl atoms.
Explanation: Ionic compound is formed by transfer of electrons from metal to non metal.
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Here magnesium is metal with atomic number 12 and chlorine is a non metal with atomic number of 17.
Thus magnesium loses two electrons to form and chlorine atoms gain one electron each to form
Thus the compound formed is .