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valina [46]
2 years ago
9

since your car had a cylinder volume of 275cm what is its engine displacement if the engine had 4 cylinders​

Engineering
1 answer:
RUDIKE [14]2 years ago
5 0

Answer:

$$\begin{align*}

P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).

Explanation:

P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).

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Just need someone to talk to pls dont just use me for points
Allushta [10]

Answer:

well what do you wanna talk about friend?

Explanation:

7 0
2 years ago
Who is father of Engineer?
3241004551 [841]

John Smeatom, U.K. 18th century, was the first self-proclaimed, civil engineer in the 18th century and IS considered “the father of modern, civil engineering”.

hoped this helped! :)

4 0
3 years ago
Read 2 more answers
There are three options for heating a particular house: a. Gas: $1.33/therm where 1 therm=105,500 kJ b. Electric Resistance: $0.
sergejj [24]

Answer:

Option ‘a’ is the cheapest for this house.

Explanation:

Cheapest method of heating must have least cost per kj of energy. So, convert all the energy in the same unit (say kj) and take select the cheapest method to heat the house.

Given:

Three methods are given to heat a particular house are as follows:

Method (a)

Through Gas, this gives energy of amount $1.33/therm.

Method (b)

Through electric resistance, this gives energy of amount $0.12/KWh.

Method (c)

Through oil, this gives energy of amount $2.30/gallon.

Calculation:

Step1

Change therm to kj in method ‘a’ as follows:

C_{1}=\frac{\$ 1.33}{therm}\times(\frac{1therm}{105500kj})

C_{1}=1.2606\times10^{-5} $/kj.

Step2

Change kWh to kj in method ‘b’ as follows:

C_{2}=\frac{\$ 0.12}{kWh}\times(\frac{1 kWh }{3600kj})

C_{2}=3.334\times10^{-5} $/kj.

Step3

Change kWh to kj in method ‘c’ as follows:

C_{3}=\frac{\$ 2.30}{gallon}\times(\frac{1 gallon }{138500kj})

C_{3}=1.66\times10^{-5} $/kj.

Thus, the method ‘a’ has least cost as compare to method b and c.

So, option ‘a’ is the cheapest for this house.

 

5 0
2 years ago
A water-filled manometer is used to measure the pressure in an air-filled tank. One leg of the manometer is open to atmosphere.
ddd [48]

Answer:

P = 150.335\,kPa (Option B)

Explanation:

The absolute pressure of the air-filled tank is:

P = 101.3\,kPa + \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{kg}{m^{3}} \right)\cdot (5\,m)\cdot \left(\frac{1\,kPa}{1000\,Pa} \right)

P = 150.335\,kPa

4 0
3 years ago
Force = 33 newtons
kicyunya [14]

Answer:

answer

Explanation:

4 0
2 years ago
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