Answer: no solution
Step-by-step explanation:
Answer:
okay depending on the question
1. y - y₁ = m(x - x₁)
y - (-7) = 6(x - (-8))
y + 7 = 6(x + 8)
y + 7 = 6(x) + 6(8)
y + 7 = 6x + 48
<u> - 7 - 7</u>
y = 6x + 41
2. <u>y₂ - y₁</u> = <u>-8 - (-3)</u> = <u>-8</u><u> + 3</u> = <u>-5</u> = -1²/₃
x₂ - x₁ -1 - (-4) -1 + 4 3
3. 2x - 3y = 11
<u>3x + 3y = 9</u>
<u>5x</u> = <u>20</u>
5 5
x = 4
2x - 3y = 11
2(4) - 3y = 11
8 - 3y = 11
<u>- 8 - 8</u>
<u>-3y</u> = <u>3</u>
-3 -3
y = -1
(x, y) = (4, -1)
4. 2x - 5y = -7 ⇒ -6x + 15y = 21
5x - 3y = 11 ⇒ <u>-25x + 15y = -55</u>
<u>19x</u> = <u>76</u>
19 19
x = 4
2x - 5y = -7
2(4) - 5y = -7
8 - 5y = -7
<u>- 8 - 8</u>
<u>-5y</u> = <u>-15</u>
-5 -5
y = 3
(x, y) = (4, 3)
5. 4.9 × 10¹¹, 8.9 × 10¹⁸, 1.3 × 10⁸, 6.7 × 10⁸, 2.7 × 10⁸
<u>1.3 × 10³</u>, 2.7 × 10⁸, 6.7 × 10⁸, 4.9 × 10¹¹, <u>8.9 × 10¹⁸</u>
Least Greatest
A graphing calculator shows four (4) zeros of
f(x) = sin(2x -9°) -cos(x +30°)
in the range 0° ≤ x ≤ 360°
Solutions are
x ∈ {23°, 129°, 143°, 263°).
_____
You can make use of a couple of trig identities to rearrange this equation.
cos(x) = sin(x+90°)
sin(a) -sin(b) = 2*cos((a+b)/2)*sin((a-b)/2)
So
sin(2x -9°) -sin(x +120°) = 2*cos((3x +111°)/2)*sin((x -129°)/2) = 0
The cosine factor will be zero for
(3x +111°)/2 = n*180° +90°
3x -69° = n*360°
x = 23° +n*120° . . . . . . for any integer n
The sine factor will be zero for
(x -129°)/2 = n*180°
x = 129° +n*360° . . . . . for any integer n
Combined, these solutions give the ones listed above in the range 0..360°.