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Arada [10]
2 years ago
14

Describe free fall and weightlessness ?​

Physics
1 answer:
yaroslaw [1]2 years ago
8 0

weightlessness is the complete or near complete absense of the sensation of weight.

when in freefall,the only force acting upon your body is the force of gravity a noun contact force.since the gravity cannot be felt without any other opposing forces,you would have no sensation of it.you would feel weightless when in a state of freefall.

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The bodies in this universe attract one another name the scientist who propounded this statement​
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7 0
2 years ago
11. A 6.0‐m wire with a mass of 50 g, is under tension. A transverse wave, for which the frequency is 810 Hz, the wavelength is
Irina-Kira [14]

Answer:

Time will be 19 ms so option (a) is correct option

Explanation:

We have given that mass of wire m = 50 gram = 0.5 kg

Frequency f = 810 Hz

Wavelength = 0.4 m

Velocity is given by

v=wavelength\times frequency=810\times 0.4=324m/sec

Amplitude is given as d = 6 m

So time t=\frac{distance}{velocity}=\frac{6}{324}=0.01851=19ms

So option (a) is correct option

4 0
3 years ago
A 1.50-V battery supplies 0.414 W of power to a small flashlight. If the battery moves 4.93 1020 electrons between its terminals
slamgirl [31]

Answer:

2.86×10⁻¹⁸ seconds

Explanation:

Applying,

P = VI................ Equation 1

Where P = Power, V = Voltage, I = Current.

make I the subject of the equation

I = P/V................ Equation 2

From the question,

Given: P = 0.414 W, V = 1.50 V

Substitute into equation 2

I = 0.414/1.50

I = 0.276 A

Also,

Q = It............... Equation 3

Where Q = amount of charge, t = time

make t the subject of the equation

t = Q/I.................. Equation 4

From the question,

4.931020 electrons has a charge of (4.931020×1.6020×10⁻¹⁹) coulombs

Q = 7.899×10⁻¹⁹ C

Substitute these value into equation 4

t =  7.899×10⁻¹⁹/0.276

t = 2.86×10⁻¹⁸ seconds

5 0
3 years ago
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Serhud [2]

it is true. the trajectory reaches the value of zero at the top

4 0
3 years ago
If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front o
Svetach [21]
C.
18 / x = 12 / 4
12x = 72
x = 6mm
6 0
3 years ago
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