Use any letter "x" is the usual one but since you have 2 you can use 2 different ones.
Because of the symmetry, we can just go from x=0 to x=2 to find the area between
<span>y = x^2 and y = 4 </span>
<span>that area = ∫4-x^2 dx from 0 to 2 </span>
<span>= [4x - (1/3)x^3] from 0 to 2 </span>
<span>= 8 - 8/3 - 0 </span>
<span>= 16/3 </span>
<span>so when y = b </span>
<span>x= √b </span>
<span>and we have the area as </span>
<span>∫(b - x^2) dx from 0 to √b </span>
<span>= [b x - (1/3)x^3] from 0 to √b </span>
<span>= b√b - (1/3)b√b - 0 </span>
<span>(2/3)b√b = 8/3 </span>
<span>b√b =4 </span>
<span>square both sides </span>
<span>b^3 = 16 </span>
<span>b = 16^(1/3) = 2 cuberoot(2) </span>
<span>or appr 2.52</span>
Answer:
<h3>n=1,</h3>
=5
<h3>n =2,</h3>
=15
<h3>n=3</h3>
=33
Step-by-step explanation:
Answer:
y=x no
y=12x yes
y=1.6x yes
y=3/(4x) no
y=2x+1 no
y=3+x no
Step-by-step explanation: