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xenn [34]
3 years ago
15

Y=2x and 5x-y=9 substitution

Mathematics
2 answers:
grandymaker [24]3 years ago
7 0
1. Substitute 2x for y: 5x-2x=9
2. Combine like terms: 3x=9
3. Divide each side by 3: x=3
Naily [24]3 years ago
6 0

Answer:

3,6

Step-by-step explanation:

Plug 2x(y) into 5x -y = 9

5x -2x = 9

Add like terms.

3x = 9

Divide both sides by 3.

x = 3

Now, in order to find y, plug 3(x) into y = 2x

y = 2(3)

y = 6

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3 years ago
The shear strength of each of ten test spot welds is determined, yielding the following data (psi).
Mumz [18]

Answer:

a) Mean = 382.3 psi

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b) 392.7 psi

c) P(X<400)=0.8026

Step-by-step explanation:

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M=\frac{1}{n}\sum x_i=\frac{1}{10}(389+405+409+367+358+415+376+375+367+362)\\\\M=\frac{1}{10}(3823)=382.3\\\\\mu\approx M=382.3

s=\sqrt{\frac{1}{n-1}\sum (x_i-M)^2}=\sqrt{\frac{1}{10-1}(389-382.3)^2+...+(362-383.2)^2}\\\\\\s=\sqrt{\frac{1}{9}(3906.1)}=\sqrt{434}=20.8\\\\\\\sigma\approx s=20.8

b) We start by searching for the z-value for the 95th percentile. This value is

z=1.645:

P(z

Then, the strength value below which 95% of all welds will have their strengths is:

X=\mu+z\cdot \sigma/\sqrt{n}=382.3+1.645*20.8/\sqrt{10}\\\\X=382.3+32.9/3.2=382.3+10.4\\\\X=392.7

c) We calculate the probability of X being equal or less than 400 as:

z=(X-\mu)/\sigma=(400-382.3)/20.8=17.7/20.8=0.851\\\\\\P(X\leq400)=P(z

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3 years ago
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Jobisdone [24]

Answer:

Slope is -5/3

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