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german
3 years ago
12

If V= 1/3Bh, then what is the value of B? Pls answer I need help with this question

Mathematics
1 answer:
gladu [14]3 years ago
5 0

Answer:

Well B is the base of the shape

If thats what you mean

Step-by-step explanation:

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Find the equation of the line passing through the points (3,-2) and (4,6) in slope intercept form.​
noname [10]

Hey!

------------------------------------------------

They already give us the slope, so we can solve the y-intercept.

We can use (3, -2).

y = 8x + b

-2 = 8(3) + b

-2 = 24 + b

-2 - 24 = 24 + b - 24

-26 = b

------------------------------------------------

Hence, the answer is \Large\boxed{\mathsf{y~=~8x~+~-26}}

------------------------------------------------

Hope This Helped! Good Luck!

4 0
3 years ago
2. In what ratio does the point (5, 4) divide the given line joining the points (2,1) and (7,6)​
Darya [45]

Answer:

3/2

Step-by-step explanation:

Let it be

C (5;4) , A (2;1) ; B(7;6)

Suppose that C divide the line AB in ratio m/n from point A (AC is m, CB is n)

Use the formula xc=(m*xb+n*xa)/ (m+n)

5=(m*7+2n)/(m+n)

5m+5n= 7m+2n

2m=3n

m/n=3/2

5 0
2 years ago
HELP WITH THESE QUESTIONS PART 2... 1 Question
Lunna [17]

<u>Step-by-step explanation</u> and Answers:

(\frac{1}{\sqrt{10}},\frac{3}{\sqrt{10}}) is in the format (cos, sin). So, adjacent = 1, opposite = 3, hypotenuse = \sqrt{10}

sin = \frac{opposite}{hypotenuse} = \frac{3}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}}) = \frac{3\sqrt{10}}{10}

cos =  \frac{adjacent}{hypotenuse} = \frac{1}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}}) = \frac{\sqrt{10}}{10}

tan = \frac{opposite}{adjacent} = \frac{3}{1} = 3

csc = \frac{hypotenuse}{opposite} = \frac{\sqrt{10}}{3}

sec = \frac{hypotenuse}{adjacent} = \frac{\sqrt{10}}{1} = \sqrt{10}

cot = \frac{adjacent}{opposite} = \frac{1}{3}

7 0
3 years ago
A circle is centered at the point (5,-4) And passes through the point (-3,2). What is the equation of the circle?
Natalka [10]
The equation of a circle is:

(x-h)2 + (y-k)2 = r2

where (h,k) is the location of the center and r is the radius. So we need to find h, k, and r. The center is given as (5,-4) so h = 5 and k = -4:

(x-5)2 + (y-(-4))2 = r2
(x-5)2 + (y+4)2 = r2

So we need to find r. Use the distance formula to find the distance between (5,-4) and (-3,2):

r = [(5-(-3))2+((-4)-2)2]1/2
r = [82 + (-6)2]1/2
r = [64 + 36]1/2
r = 1001/2

r= 10

The final equation is:

(x-5)2 + (y+4)2 = 102
8 0
3 years ago
Annuity A pays 1 at the beginning of each year for three years. Annuity B pays 1 at the end of each year for four years. The Mac
kiruha [24]

Answer:

Calculate the Macaulay duration of Annuity B at the time of purchase is 1.369.

Step-by-step explanation:

First, we use 0.93 to calculate the v which equals 1/(1+i).

\frac{0+1*v+2v^{2} }{1+v+v^{2} } = 0.93

After rearranging the equation, we get 1.07v^{2} + 0.07v - 0.93=0

So, v=0.9

Mac D: \frac{0+1*v+2*v^{2}+ 3*v^{2} }{1+v+v^{2}+ v^{3} }

After substituting the value of v, we get Mac D = 1.369.

7 0
3 years ago
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