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4 years ago

13

***PLEASE HELP WITH ANSWER AND EXPLANATION: Imagine the current in a current-carrying wire is flowing into the screen. What is t

he direction of the magnetic field around this current?
The magnetic field is clockwise.
The magnetic field is counterclockwise.
The magnetic field is moving out of the screen.
The magnetic field is moving into the screen.

2 answers:

DerKrebs [107]4 years ago

7 0

Answer:

the magnetic field is clockwise

Explanation:

aalyn [17]4 years ago

5 0

Magnetic field direction is given by right hand thumb rule.

If we put our thumb in the direction of current then curl of fingers will show the magnetic field direction around the wire.

Now here since current is going into the screen so we will put our thumb into the screen and then the curl of fingers is clockwise around it.

The magnetic field is clockwise.

So this would be the direction of magnetic field

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Answer:

Explanation:

When the body has mass m

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F=ma

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Then,

When you the mass is quadruple

i.e M=4m.

Then, let assume you are applying the same force

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F=4ma

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Answer:

<em>The two balls pass each other at a height of 5.53 m</em>

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Explanation:

<u>Vertical Motion</u>

An object thrown from the ground at speed vo, is at a height y given by:

$y=vo.t-g.t^2/2$

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$y=g.t^2/2$

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$H = h-g.t^2/2$

The question describes that ball 1 is dropped from a height of h=22 m. At the same time, ball 2 is thrown straight up with vo=12 m/s.

We want to find at what height both balls coincide. We'll do it by finding the time when it happens. We have written the equations for the height of both balls, we only have to equate them:

$vo.t-g.t^2/2=h-g.t^2/2$

Simplifying:

$vo.t=h$

Solving for t:

$t=h/vo=22/12=1.833\ s$

The height of ball 1 is:

$H = 22-9.8.(1.833)^2/2$

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$y=12\cdot(1.833)-9.8\cdot(1.833)^2/2$

y=5.53 m

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$vf1=g.t=9.8\cdot 1.833=17.97\ m/s$

vf1=17.97 m/s

The speed of the second ball is:

$vf2=vo-gt=12-9.8\cdot 1.833=-5.96\ m/s$

vf2=-5.96 m/s

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3 years ago

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3 years ago

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Answer:

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Just one root offers a solution that is physically reasonable:

$t = 4.449\,s$

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