Peat, which is formed when decayed moss is compressed over time, is used for which purpose?

Calculate the heat absorbed/released (in Joules) by the solution when the cold pack solid dissolved in water in your experiment.

skad [1K]

Answer:

56765

Explanation:

i did the math and this is the answer

8 0

2 years ago

In a particular breed of cattle, a black coat is dominant over a red coat. If a cow with a red coat is crossed with a black bull

larisa86 [58]

C.75%. Because the B is dominant

3 0

3 years ago

Kira dissolved different solutes in 100 ml of water. She recorded the amount of each solute that would dissolve at different tem

Radda [10]

This information confirms that temperature and solubility are related. The higher the temperature is, the more soluble.

8 0

1 year ago

27/13Al+4/2He >>>> 30/15P+

Veseljchak [2.6K]

Answer

Explanation:

27/13Al+4/2He >>>> 30/15P+

5 0

3 years ago

A buret is filled with 0.1517 M A 25.0 mL portion of an unknown acid and two drops of indicator are added to an Erlenmeyer flask

erik [133]

Answer:

Molarity of Unknown Acid = 0.1332 M

Explanation:

Data for solving problem:

Molarity of base in buret (M₁)= 0.1517 M

volume of the acid in Erlenmeyer flask (V₂)= 25.0 mL

Volume of the base in the buret (V₁) = final volume of buret - initial volume in buret

final volume of buret = 22.5 mL

initial volume in buret = 0.55 mL

So

Volume of the base in the buret (V₁) = 22.5 mL -0.55 mL = 21.95 mL

Volume of the base in the buret (V₁) = 21.95 mL

Molarity of Unknown acid in the Erlenmeyer flask (M₂) = To be find

Explanation:

It is acid base titration and formula for this titration is as follows:

Molarity of base x Volume of base = Molarity of acid x volume of acid

it can be written as

M₁V₁ = M₂V₂ -------------------- equation (1)

we have to find M₂

so by rearrangment the equation (1)

M₁V₁ / V₂ = M₂ ------------------ equation (2)

put the values in equation in equation (2)

M₂ = 0.1517 M x 21.95 mL / 25.0 mL

M₂ = 3.3298 /25.0

M₂ = 0.1332 M

so the Molarity of Unknown acid is <u>0.1332 M</u>

5 0

3 years ago