Answer/Explanation:
STR analysis
Short tandem repeats (STRs) are the genetic information present in the FBI's database. These are repetitive regions of the genome, and used for DNA profiling in a variety of applications. They can be used to discriminate between non-related individuals, as people have different numbers of repeating units. A combination of approximately 13 regions are analysed, giving a unique genetic fingerprint
mtDNA analysis
mt DNA is mitochondrial DNA. This type of analysis can trace the maternal lineage of a person, as mitochondrial DNA is inherited from the mother, and is largely unchanged throughout a maternal line. This is often useful when DNA is too degraded to obtain accurate STRs, as there are many more copies of mtDNA in the cell than nuclear DNA. It is also useful for linking missing relatives.
Explanation:
When fluorine gas reacts with calcium metal at high temperatures then it results into the formation of calcium fluoride.
Since, calcium has 2 extra electrons as its electronic distribution is 2, 8, 8, 2. Whereas each fluorine atom needs one electron to complete its octet.
Therefore, the chemical reaction equation will be as follows.
Answer:
So X has an atomic mass of 55.05 u, and is probably Mn
Explanation:
<u>Step1: </u>Balance the equation
XI2 +Cl2 → XCl2 + I2
<u>Step2:</u> find the molar mass of the compounds
<em><u>Compounds : </u></em>
X ⇒ Molar mass = M
XI2 ⇒ Molar mass = M + 2*126.9 u
XCl2 ⇒Molar mass = M + 2*35.45u
⇒For 1 mole XI2 we have 1 mole Cl2 reacting , as well as 1 mole XCl2 and 1 mole I2 produced.
<u>Step 3:</u> Calculating the atomic mass
(1.383g * XI2) / (M + 2*126.90 u) = (0.564g * XCl2) / ( M + 2 * 35.45u)
1.383 (M + 2 *35.45 u )= 0.564 (M + 2*126.90)
1.383M + 98.0547 = 0.564 M + 143.1432
1.383 M - 0.564 M =143.1432 - 98.0547
0.819 M = 45.0885
M = 55.05 u
So X has an atomic mass of 55.05 u ⇒ if we look at the periodic table we can find that the closest element is Manganese (Mn)
MnI2 + Cl2 → MnCl2 + I2
How big are the buckets and how much do each golf ball weigh. I need more specifics plzzz
Answer:
1.43 (w/w %)
Explanation:
HCl reacts with NH3 as follows:
HCl + NH3 → NH4+ + Cl-
<em>1 mole of HCl reacts per mole of ammonia.</em>
Mass of NH3 is obtained as follows:
<em>Moles HCl:</em>
0.02999L * (0.1068mol / L) = 3.203x10-3 moles HCl = <em>Moles NH3</em>
<em>Mass NH3 in the aliquot:</em>
3.203x10-3 moles NH3 * (17.031g / mol) = 0.0545g.
Mass of sample + water = 22.225g + 75.815g = 98.04g
Dilution factor: 98.04g / 14.842g = 6.6056
That means mass of NH3 in the sample is:
0.0545g * 6.6056 = 0.36g NH3
Weight percent is:
0.36g NH3 / 25.225g * 100
<h3>1.43 (w/w %)</h3>