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aalyn [17]
3 years ago
5

Which statement(s) correctly compare the masses of protons, neutrons, and electrons? Check all that apply

Physics
2 answers:
Elza [17]3 years ago
8 0

Answer: A & F

__Protons and neutrons have similar mass.

__Electrons are smaller than a proton or a neutron.

Explanation:

umka21 [38]3 years ago
3 0

__Protons and neutrons have similar mass.

__Electrons are smaller than a proton or a neutron.

Explanation:

The three particles involved in this problem are:

  • Proton: it is positively charge, it is found in the nucleus of the atom, and its mass is m_p = 1.67 \cdot 10^{-27} kg
  • Neutron: it has no electric charge, it is also found in the nucleus of the atom, and its mass is approximately equal to that of the proton (just slightly larger)
  • Electron: it has negative electric charge, it orbit around the nucleus of the atom, and its mass is much smaller than that of the proton: m_e = 9.11 \cdot 10^{-31} kg

We can now analyze each of the given statement:

__Protons and neutrons have similar mass.  --> TRUE

__Protons and electrons have similar mass.  --> FALSE, the electron is much lighter

__Neutrons and electrons have similar mass.  --> FALSE, the neutron is much heavier

__Protons are smaller than a neutron or an electron.  --> FALSE, protons are similar to the neutrons

__Neutrons are smaller than a proton or an electron.  --> FALSE, neutrons are similar to the protons

__Electrons are smaller than a proton or a neutron. --> TRUE

Learn more about atoms:

brainly.com/question/2757829

#LearnwithBrainly

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Explanation:

As the given data is as follows.

    R_{1} = 680 \ohm ohm\ohm,    R_{2} = 720 \ohm ohm,

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(a)   We will calculate the maximum resistance by combining the given resistances as follows.

      Max. Resistance = R_{1} + R_{2} + R_{3}

                                  = (680 + 720 + 1200) \ohm ohm

                                  = 2600 ohm

or,                               = 2.6 k\ohm ohm

Therefore, the maximum resistance you can obtain by combining these is 2.6 k\ohm ohm.

(b)   Now, the minimum resistance is calculated as follows.

      Min. Resistance = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}}

                                 = \frac{1}{680} + \frac{1}{720} + \frac{1}{1200}

                                 = 3.683 \times 10^{-3} ohm

Hence, we can conclude that minimum resistance you can obtain by combining these is 3.683 \times 10^{-3} ohm.

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Use Eq. cosϕ=R/Z to show that the average power delivered by the source in an L−R−C series circuit is given by Pav = I^2rmsR .
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Answer:

Explanation:

In a L C R circuit, the average power is given by

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