Which statement(s) correctly compare the masses of protons, neutrons, and electrons? Check all that apply
2 answers:
__Protons and neutrons have similar mass.
__Electrons are smaller than a proton or a neutron.
Explanation:
The three particles involved in this problem are:
- Proton: it is positively charge, it is found in the nucleus of the atom, and its mass is
- Neutron: it has no electric charge, it is also found in the nucleus of the atom, and its mass is approximately equal to that of the proton (just slightly larger)
- Electron: it has negative electric charge, it orbit around the nucleus of the atom, and its mass is much smaller than that of the proton:
We can now analyze each of the given statement:
__Protons and neutrons have similar mass. --> TRUE
__Protons and electrons have similar mass. --> FALSE, the electron is much lighter
__Neutrons and electrons have similar mass. --> FALSE, the neutron is much heavier
__Protons are smaller than a neutron or an electron. --> FALSE, protons are similar to the neutrons
__Neutrons are smaller than a proton or an electron. --> FALSE, neutrons are similar to the protons
__Electrons are smaller than a proton or a neutron. --> TRUE
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Answer:
Explanation:
mass attached m = .14 kg
force constant k = 5N / m
displacement
= amplitude of oscillation
A = .03 m
A ) period of motion =
= 2 x 3.14
T = 1.05 s
B ) maximum speed of block = angular velocity x amplitude
= (2π /T) x A
= (2 x 3.14 x .03) / 1.05
= .1794 m / s
17.94 cm /s
C )
maximum acceleration = angular velocity² x amplitude
= (2π /T)² x A
= (2π /1.05)² x .03
= 1.073 m / s²
D )
position
S = A cos ωt , ω is angular velocity
S = .03 cos(2πt /T)
= .03 cos 5.98 t
v =ω A sin(2πt /T)
= 5.98 x .03 sin5.98t
= .1794 sin5.98t
acceleration = ω²A sin5.98t
= 1.073 sin5.98t
Answer:
steady state temperature =88.7deg C
t=time within 1 deg C of it steady state is 8.31s
Explanation:
A 1 m long wire of diameter 1mm is submerged in an oil bath of temperature 25-degC. The wire has an electrical resistance per unit length of 0.01 Ω/m. If a current of 100 A flows through the wire and the convection coefficient is 500W/m2K, what is the steady state temperature of the wire? From the time the current is applied, how long does it take for the wire to reach a temperature within 1-degC of the steady state value? The density of the wire is 8,000kg/m3, its heat capacity is 500 J/kgK and its thermal condu
The diameter of the wire is known to be=1mm
properties=
The density of the wire is 8,000 kg/m3,
heat capacity is 500 J/kgK
themal conductivity is 20W/m.K
electrical resistance per unit length of 0.01 Ω/m
from lump capavity method
500*(2.5*10^-4)/20
0.006<0.1
we know also, to find steady state temperature
Dh(T-Tinf)=
make T the subject of the equation , we have
T=25+
T=88.7 degC
rate of chnage in temperature
dT/dt=
at t=o and integrating both sides
we have
t=8.31s
steady state temperature =88.7deg C
t=time within 1 degC of it steady stae is 8.31s