Which statement(s) correctly compare the masses of protons, neutrons, and electrons? Check all that apply
2 answers:
__Protons and neutrons have similar mass.
__Electrons are smaller than a proton or a neutron.
Explanation:
The three particles involved in this problem are:
- Proton: it is positively charge, it is found in the nucleus of the atom, and its mass is
- Neutron: it has no electric charge, it is also found in the nucleus of the atom, and its mass is approximately equal to that of the proton (just slightly larger)
- Electron: it has negative electric charge, it orbit around the nucleus of the atom, and its mass is much smaller than that of the proton:
We can now analyze each of the given statement:
__Protons and neutrons have similar mass. --> TRUE
__Protons and electrons have similar mass. --> FALSE, the electron is much lighter
__Neutrons and electrons have similar mass. --> FALSE, the neutron is much heavier
__Protons are smaller than a neutron or an electron. --> FALSE, protons are similar to the neutrons
__Neutrons are smaller than a proton or an electron. --> FALSE, neutrons are similar to the protons
__Electrons are smaller than a proton or a neutron. --> TRUE
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chuyển động chậm dầnđều
Answer:
The acceleration that the jet liner that must have is 2.241 meters per square second.
Explanation:
Let suppose that the jet liner accelerates uniformly. From statement we know the initial () and final speeds (
), measured in meters per second, of the aircraft and likewise the runway length (
), measured in meters. The following kinematic equation is used to calculate the minimum acceleration needed (
), measured in meters per square second:
If we know that ,
and
, then the acceleration that the jet must have is:
The acceleration that the jet liner that must have is 2.241 meters per square second.
Answer:
and
Explanation:
Given:
- first charge,
- second charge,
- position of first charge,
- position of second charge,
Now since there are only 2 charges and of the same sign so they repel each other. This repulsion will be zero at some point on the line joining the charges.
<u>Now, according to the condition, electric field will be zero where the effects of field due to both the charges is equal.</u>
- since first charge is greater than the second charge so we may get a point to the right of the second charge and the distance between the two charges is 1 meter.
Since we have assumed that the we may get a point to the right of second charge so we calculate with respect to the origin.
and