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aalyn [17]
3 years ago
5

Which statement(s) correctly compare the masses of protons, neutrons, and electrons? Check all that apply

Physics
2 answers:
Elza [17]3 years ago
8 0

Answer: A & F

__Protons and neutrons have similar mass.

__Electrons are smaller than a proton or a neutron.

Explanation:

umka21 [38]3 years ago
3 0

__Protons and neutrons have similar mass.

__Electrons are smaller than a proton or a neutron.

Explanation:

The three particles involved in this problem are:

  • Proton: it is positively charge, it is found in the nucleus of the atom, and its mass is m_p = 1.67 \cdot 10^{-27} kg
  • Neutron: it has no electric charge, it is also found in the nucleus of the atom, and its mass is approximately equal to that of the proton (just slightly larger)
  • Electron: it has negative electric charge, it orbit around the nucleus of the atom, and its mass is much smaller than that of the proton: m_e = 9.11 \cdot 10^{-31} kg

We can now analyze each of the given statement:

__Protons and neutrons have similar mass.  --> TRUE

__Protons and electrons have similar mass.  --> FALSE, the electron is much lighter

__Neutrons and electrons have similar mass.  --> FALSE, the neutron is much heavier

__Protons are smaller than a neutron or an electron.  --> FALSE, protons are similar to the neutrons

__Neutrons are smaller than a proton or an electron.  --> FALSE, neutrons are similar to the protons

__Electrons are smaller than a proton or a neutron. --> TRUE

Learn more about atoms:

brainly.com/question/2757829

#LearnwithBrainly

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3 years ago
The position of an object in simple harmonic motion is defined by the function y = (0.50 m) sin (πt/2). Determine the maximum sp
Gnoma [55]

The maximum speed of the object under simple harmonic motion is 0.786 m/s.

The given parameters:

  • Position of the particle, y = 0.5m sin(πt/2)

<h3>Wave equation for simple harmonic motion;</h3>

y = A sin(ωt + Ф)

where;

  • A is the amplitude = 0.5 m
  • ω is the angular speed = π/2

The maximum speed of the object is calculated as follows;

V_{max} = A \omega\\\\V_{max} = 0.5 \times \frac{\pi}{2} = \frac{\pi}{4} \ m/s  = 0.786 \ m/s

Thus, the maximum speed of the object under simple harmonic motion is 0.786 m/s.

Learn more about simple harmonic motion here: brainly.com/question/17315536

5 0
2 years ago
Plzz helpppp meee!!!!
spin [16.1K]
A=f/m
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4 0
2 years ago
Read 2 more answers
The a992 steel rod bc has a diameter of 50 mm and is used as a strut to support the beam. determine the maximum intensity w of t
EastWind [94]

Answer:

w = 11.211 KN/m

Explanation:

Given:

diameter, d = 50 mm

F.S = 2

L = 3

Due to symmetry, we have:

Ay = By = \frac{w * 6}{2} = 3w

P_c_r = 3w * F.S = 3w * 2.0 = 6w

I = \frac{\pi}{64} (0.05)^4 = 3.067*10^-^7

To find the maximum intensity, w, let's take the Pcr formula, we have:

P_c_r = \frac{\pi^2 E I}{(KL)^2}

Let's take k = 1

E = 200*10^9

Substituting figures, we have:

6w = \frac{\pi^2 * 200*10^9 * 3.067*10^-^7}{(1 * 3)^2}

Solving for w, we have:

w = \frac{67266.84}{6}

w = 11211.14 N/m = 11.211 KN/m

Since Area, A= pi * (0.05)²

\sigma _c_r = \frac{w}{A}

\sigma _c_r = \frac{11.211}{\pi (0.05)^2} = 1.4 MPA < \sigma y. This means it is safe

The maximum intensity w = 11.211KN/m

3 0
3 years ago
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