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3 years ago

Which statement(s) correctly compare the masses of protons, neutrons, and electrons? Check all that apply

Physics

2 answers:

Elza [17]3 years ago

8 0

Answer: A & F

__Protons and neutrons have similar mass.

__Electrons are smaller than a proton or a neutron.

Explanation:

umka21 [38]3 years ago

3 0

__Protons and neutrons have similar mass.

__Electrons are smaller than a proton or a neutron.

Explanation:

The three particles involved in this problem are:

Proton: it is positively charge, it is found in the nucleus of the atom, and its mass is $m_p = 1.67 \cdot 10^{-27} kg$
Neutron: it has no electric charge, it is also found in the nucleus of the atom, and its mass is approximately equal to that of the proton (just slightly larger)
Electron: it has negative electric charge, it orbit around the nucleus of the atom, and its mass is much smaller than that of the proton: $m_e = 9.11 \cdot 10^{-31} kg$

We can now analyze each of the given statement:

__Protons and neutrons have similar mass. --> TRUE

__Protons and electrons have similar mass. --> FALSE, the electron is much lighter

__Neutrons and electrons have similar mass. --> FALSE, the neutron is much heavier

__Protons are smaller than a neutron or an electron. --> FALSE, protons are similar to the neutrons

__Neutrons are smaller than a proton or an electron. --> FALSE, neutrons are similar to the protons

__Electrons are smaller than a proton or a neutron. --> TRUE

Learn more about atoms:

brainly.com/question/2757829

#LearnwithBrainly

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A student drops an object out the window of the top floor of a high-rise dormitory.

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Now we can switch over to the metric system, where the acceleration
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2 years ago

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3 years ago

Charge g is distributed in a spherically symmetric ball of radius a. (a) Evaluate the average volume charge density p. (b) Now a

nasty-shy [4]

Answer:

Explanation:

The volume of a sphere is:

V = 4/3 * π * a^3

The volume charge density would then be:

p = Q/V

p = 3*Q/(4 * π * a^3)

If the charge density depends on the radius:

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I integrate the charge density in spherical coordinates. The charge density integrated in the whole volume is equal to total charge.

$Q = \int\limits^{2*\pi}_0\int\limits^\pi_0 \int\limits^r_0 {k * r} \, dr * r*d\theta* r*d\phi$

$Q = k *\int\limits^{2*\pi}_0\int\limits^\pi_0 \int\limits^r_0 {r^3} \, dr * d\theta* d\phi$

$Q = k *\int\limits^{2*\pi}_0\int\limits^\pi_0 {\frac{r^4}{4}} \, d\theta* d\phi$

$Q = k *\int\limits^{2*\pi}_0 {\frac{\pi r^4}{4}} \, d\phi$

$Q = \frac{\pi^2 r^4}{2}}$

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