Answer:
Sample Response: In a vacuum, there are no atoms or particles that interfere with the path of light. However, in other media, the speed of light is lower than 3.0 × 108 m/s because the wave is continuously absorbed and re-emitted by each atom in its path. The differences in speed are due to the composition of the medium and the density of the particles in the medium.
Explanation:
The answer would be Newton’s Second Law
Answer:
Amplitude will be equal to 0.091 m
Explanation:
Given mass of the slits = 41 gram = 0.041 kg
Frequency f = 1.65 Hz
So angular frequency ![\omega =2\pi f=2\times 3.14\times 1.65=10.362rad/sec](https://tex.z-dn.net/?f=%5Comega%20%3D2%5Cpi%20f%3D2%5Ctimes%203.14%5Ctimes%201.65%3D10.362rad%2Fsec)
Angular frequency is equal to ![\omega =\sqrt{\frac{k}{m}}](https://tex.z-dn.net/?f=%5Comega%20%3D%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%7D)
![10.362 =\sqrt{\frac{k}{0.041}}](https://tex.z-dn.net/?f=10.362%20%3D%5Csqrt%7B%5Cfrac%7Bk%7D%7B0.041%7D%7D)
Squaring both side
![107.371 ={\frac{k}{0.041}}](https://tex.z-dn.net/?f=107.371%20%3D%7B%5Cfrac%7Bk%7D%7B0.041%7D%7D)
k = 4.40 N/m
For vertical osculation
![mg=kA](https://tex.z-dn.net/?f=mg%3DkA)
![0.041\times 9.8=4.40\times A](https://tex.z-dn.net/?f=0.041%5Ctimes%209.8%3D4.40%5Ctimes%20A)
A = 0.091 m
So amplitude will be equal to 0.0391 m
<span>For precipitation to form, cloud droplets must grow in volume by roughly one million times.
Hope I helped :)</span>