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3 years ago

5x=2x-2+2x is true for

Mathematics

1 answer:

Svet_ta [14]3 years ago

3 0

X=-2 is the answer to your question.

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I need help with this question!

Anna [14]

Answer:

c. $660

Step-by-step explanation:

The area of the arc can be computed as the product of the length of its centerline and its width. The centerline has a radius of 5.25 ft (= (4+6.5)/2) and subtends an angle of 72π/180 radians. Thus, the area is ...

(72π/180)·(5.25 ft)·(2.5 ft)

This is multiplied by the cost per square foot to get the total cost. The calculation and its result are shown in the attachment.

The cost is about $660.

8 0

4 years ago

Prove that P(2,3), (3, 4), R(5, 6) and S(4,5) are the vertices of a rhombus

MatroZZZ [7]

Solution :-

Given coordinates to us are ,

P(2,3) .
Q(3,4).
R(5,6)
S(4,5)

Here it is asked to Prove that these are vertices of Rhombus . So we know that all sides of a Rhombus are equal .So if we show that value of all sides lenght are equal , then it will be a Rhombus .

We will use Distance Formula .

Now , here ,

Distance between P and Q :

⇒ x = √ (2 - 3)² + (3-4)² .

⇒ x = √ (-1)² + (-1)² .

⇒ x = √ 1 + 1 .

⇒ x = √2 .

Distance between Q and S :

⇒ x =√ [ (3-4)² + (5-4)².

⇒x = √ 1² + 1² .

⇒ x = √ 1 + 1 .

⇒ x = √2 .

Similarly we can prove other distances equal.

3 0

4 years ago

Simplify 3x + 3 + 2. 3x + 5 5x + 3 8x

Pie

Answer:

3x + 5

Step-by-step explanation:

We are doing variables and simplifying.

You have two types of numbers here, you have a coefficient, and you have regular numbers. Now do keep in mind that you can never add a regular number to a coefficient. So the only thing in this problem you will add is 3 and 2. Because 3x is different

3x + (3 + 2)

3x + 5

6 0

3 years ago

Read 2 more answers

A mountain climber is standing at the top of Mount Everest. The distance from the summit to the horizon is 210 miles. About how

igor_vitrenko [27]

Let DE, the height of mount Everest be x.

The center of the earth (point C), the horizont vanishing point (point H) and the top of mount Everest (point E) form a right triangle, where:

the hypothenuse is |EC|=|ED|+|DC|=x+4000 (DC is a radius)
|HC|=4000 mi
|HE|=210 mi

by the Pythagorean theorem:

$(x+4000)^{2}= 4000^{2} + 210^{2}$

$(x+4000)^{2}=16000000+44100=16044100$

taking the square roots of both sides we get:

$x+4000=+- \sqrt{16044100} =+-4005.5087$

so x=-4000+4005.5087 miles = 5.5087 miles
or x= -4000-4005.5 which is negative so not a solution to our problem

Answer: 5.5087 miles

7 0

4 years ago

HELP PLZ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Bas_tet [7]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers