The rate constant of the reaction K we can get it from this formula:
K=㏑2/ t1/2 and when we have this given (missing in question):
that we have one jar is labeled t = 0 S and has 16 yellow spheres inside and the jar beside it labeled t= 10 and has 8 yellow spheres and 8 blue spheres and the yellow spheres represent the reactants A and the blue represent the products B
So when after 10 s and we were having 16 yellow spheres as reactants and becomes 8 yellow and 8 blue spheres as products so it decays to the half amount so we can consider T1/2 = 10 s
a) by substitution in K formula:
∴ K = ㏑2 / 10 = 0.069
The amount of A (the reactants) after N half lives = Ao / 2^n
b) so no.of yellow spheres after 20 s (2 half-lives) = 16/2^2 = 4
and the blue spheres = Ao - no.of yellow spheres left = 16 - 4 = 12
c) The no.of yellow spheres after 30 s (3 half-lives) = 16/2^3 = 2
and the blue spheres = 16 - 2 = 14
Answer:
- To increase the temperature as it is a reactant in terms of its endothermicity.
- To remove it will enable more space for the reactant to favor its production.
- To add more reactant in order to increase its equilibrium concentration.
Explanation:
Hello,
The undergoing chemical reaction is:
Thus, in order to intensify the amount of nitrogen as the chemical reaction is endothermic, considering the Le Chatelier's principle we state:
- To increase the temperature as it is a reactant in terms of its endothermicity.
- To remove it will enable more space for the reactant to favor its production.
- To add more reactant in order to increase its equilibrium concentration.
Best regards.
The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time. In this example, distance is in metres (m) and time is in seconds (s), so the units will be in metres per second (m/s).
Answer:
40.7 kJ
Explanation:
Applying,
q = c'n.................. Equation 1
Where q = Thermal Heat, c' = Heat of vaporization of water, n = number of mole of water.
But,
n = mass(m)/Molar mass(m')
n = m/m'............... Equation 2
Substitute equation 2 into equation 1
q = c'(m/m')............. Equation 3
Given: c' = 40.650 KJ/mol, m = 18.02 g
Constant: m' = 18 g/mol
Substitute into equation 3
q = 40.650(18.02/18)
q = 40.695 kJ
q ≈ 40.7 kJ
