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Tpy6a [65]
3 years ago
12

Jack had four Snicker bars and 8 Mars bars. He randomly chose a piece of candy, ate it, then chose another. What is the probabil

ity that both candy bars were Snickers?
1/11
1/3
1/2
1/13
Mathematics
1 answer:
Harrizon [31]3 years ago
7 0

Answer:

1/3

If 4 are snickers and 8 are mars bars then 4/12 would be snickers so when you simplify 4/12 you get 1/3.

(hope this helps)

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Let's see who can do this!
aliina [53]

Answer:

28

Step-by-step explanation:

KARLEE HAS 4 PENCIL PACKS.

<h3>1 PENCIL = 1/7 of pack.</h3>

∴ 1 pack has 1/7 multiplied by X.

X/7 = 1, so X is 7.

AND THEREFORE 4 PACKS CONTAIN 7*4 = 28

6 0
2 years ago
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What is n less than 7?
Georgia [21]

n less than 7, is represented as this:

n>7

Step-by-step explanation:

You just need to think about what the question is, if it's less than, you use the > symbol to prove one variable is smaller than the other.

i hope this helps!

8 0
3 years ago
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Which one is correct? Please hurry...the audio is just reading the question.
Darina [25.2K]

Answer:

n = 18

Step-by-step explanation:

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18 * n = 12 * 27

18n = 324

n = 324/18

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7 0
3 years ago
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rewona [7]

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5 0
3 years ago
Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is f
pashok25 [27]

Answer:

0.999987

Step-by-step explanation:

Given that

The user is a legitimate one = E₁

The user is a fraudulent one = E₂

The same user originates calls from two metropolitan areas  = A

Use Bay's Theorem to solve the problem

P(E₁) = 0.0131% = 0.000131

P(E₂) = 1 - P(E₁)  = 0.999869

P(A/E₁) = 3%  = 0.03

P(A/E₂) = 30% = 0.3

Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :

P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}

=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}

\frac{0.2999607}{0.00000393+0.2999607}

\frac{0.2999607}{0.29996463}

= 0.999986898 ≈ 0.999987

6 0
3 years ago
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