Answer:
Solution that is 0.100 M CH3COOH (acetic acid)
and 0.100 M NaCH3COO (sodium acetate)
Find pH of buffer solution:
CH3COOH(aq) + H2O ↔ CH3COO-
(aq) + H3O+(aq)
[CH3COOH] [CH3COO-
] [H3O+]
initial 0.100 0.100 ≈0
-x x x
equil 0.100 – x 0.100 + x xFind pH of buffer solution:
CH3COOH(aq) + H2O ↔ CH3COO-
(aq) + H3O+(aq)
Ka = [CH3COO-
][H3O+
]
[CH 3COOH] = (.100 + x)x
(.100 - x) = 1.8 x 10-5
x = 1.80 x 10-5 M
pH = 4.7
Explanation:
Option C, slopes are same but y intercepts are different is the correct answer
Answer:
the answer is 0.041756547635452 we assume you are coverting between moles LiOH and gram
Explanation:
you can view details on each measurements units:monecular weight of LiOH or grams this compound is also known as lithium hydroxide the si base unit for amount of substance is the moles1 moles qual1 moles LiOH..... Sana makatulong sayo lods ang answer ko
It has more lines in it compared to hydrogen emission spectrum. It is mainly because the helium atom has more electrons than a hydrogen atom. Therefore, more electrons get excited when we pass a white light beam through a helium sample, and it causes the emission of more spectral lines
We have to know which do not violet octet rule.
The central atom in SF₄ does not violate the octet rule. the central atom in CF₄ does not violate the octet rule.
As per octet rule, atoms can combine either by transfer of valence electrons from one atom to another or by sharing of valence electrons in order to have an octet in their valence shell.
The central atom S of SF₄ contains 8 electrons in the valence shell. Also, C atom of CF₄ contains 8 electrons in the valence shell.
ICl₄⁻ contains 9 electrons in the outermost shell.
