A chemical change is when a substances chemical properties change, for example, baking a cake. A physical change is when the appearance/odor/texture etc. change, for example, ice melting
Answer:
The correct answers to the question are
1. Environmental variable c,
2. Input variable a,
3. Output variable b,
4. Input variable a,
5. Input variable a,
6. Input variable a
Explanation:
1. Outside temperature.
This is is an environmental variable regarding where the observation is taking place
2. Duration that the soup was heated before being put in the bowl.
This can be controlled so it is an input variable
3. Temperature of the soup in a student's bowl.
This depends on the initial temperature the soup was heated to so it is an output variable
4. Temperature level to which the soup is warmed up.
Input variable as it can be controlled o varied
5. Insulation of the bowl used for storing the soup.
This is an input variable as the type of bowl can be selected
6. Duration that the soup bowl is open when the server inserts the ladle to serve a student.
server or the operator of the cafeteria
Answer:
F = 1.6*10⁴ N
Explanation:
Given distance x = 0.15m, mass m = 1200kg, velocity v = 2m/s.
Unknown: force F
Force is given by Newton's law:
(1)
The average force to stop an object from a velocity will be the same force necessary to accelerate an object from rest to the same velocity.
The distance for an object starting from rest for a constant acceleration is given by:
(2)
The velocity for an object starting from rest for a constant acceleration:
(3)
Using equation 2 and 3 to eliminate time t:
(4)
Solving equation 4 for the acceleration a:
(5)
Using equation1 to solve for the force F:
(6)
A theoretical perspective is a set of assumptions about reality that inform the questions we ask and the kinds of answers we arrive as a result.
Answer:
The magnitude of the force of friction equals the magnitude of my push
Explanation:
Since the crate moves at a constant speed, there is no net acceleration and thus, my push is balanced by the frictional force on the crate. So, the magnitude of the force of friction equals the magnitude of my push.
Let F = push and f = frictional force and f' = net force
F - f = f' since the crate moves at constant speed, acceleration is zero and thus f' = ma = m (0) = 0
So, F - f = 0
Thus, F = f
So, the magnitude of the force of friction equals the magnitude of my push.