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nadya68 [22]
3 years ago
13

The diver on the diving board in the opening picture weight is 500 newtons. The diving board is 5 meters above the ground. What

is the diver's gravitational potential energy
Physics
1 answer:
Vika [28.1K]3 years ago
8 0

Answer: Hello!, The answer would be 500 times 5, hope this helps!

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A 98-kg fullback, running at 5.0 m/s, attempts to dive directly across the goal line for a touchdown. Just as he reaches the lin
Troyanec [42]

Answer:

(a) Explained below

(b) v_f=0.35\ m/s

(c) Yes

Explanation:

<u>Law Of Conservation Of Linear Momentum</u>

The total linear momentum of a system of particles or objects is conserved unless an external force is acting on the system. The formula for the momentum of a body with mass m and velocity v is P=mv. If there is a system of bodies, then the total linear momentum is the sum of the individual momentums

P=m_1v_1+m_2v_2+...+m_nv_n

When objects collide and join together, the only final mass is the sum of all masses, all traveling at the same speed.

Our m_1=98\ kg fullback runs at v_1=5\ m/s. Two two 68-kg linebackers attempt to stop him, one at -2.0 m/s and the other at -4.0 m/s. The negative value is because the run against the positive direction, taken in the direction of the fullback.

(a) Before the event, there is a total linear momentum, computed as the sum of the momentums of each player as shown

p_1=m_1v_1=(98)(5)=490 Kg\ m/s

p_2=m_2v_2=(68)(-4)=-272 kg\ m/s

p_3=m_3v_3=(68)(-2)=-136 kg\ m/s

p_t=p_1+p_2+p_3=390-272-136=82\ kg\ m/s

After the collision, all the players keep joined in one single mass of.

m_t=98+68+68=234\ kg

They will move at a speed which will be computed below

(b) The final momentum of the system is

p_f=m_tv_f=82\ kg\ m/s

Since the linear momentum is conserved, the final speed v_f is common to all of the players. Let's solve to find it

\displaystyle v_f=\frac{p_f}{m_t}

\displaystyle v_f=\frac{82}{234}

v_f=0.35\ m/s

(c) Since the final speed of the players is positive, it means the touchdown was actually scored, the fullback moved forward across the goal line, the positive reference.

5 0
3 years ago
A planet has a period of revolution about the sun equal to T and a mean distance from the sun equal to R. T2 varies directly as
Tamiku [17]

Answer:

T² ∝ R³

Explanation:

Given data,

The period of revolution of the planet around the sun, T

The mean distance of the planet from the sun, R

According to the III law of Kepler, " Law of Periods' states that the square of the orbital period to go around the sun once is directly proportional to the cube of the mean distance between the sun and the planet.

                              T² ∝ R³

                               \frac{T^{2}}{R^{3}} = Constant

From the above equation it is clear that T² varies directly as the R³.

7 0
3 years ago
Discuss the merits and demerits of various theories of the formation of galaxies.​
Sedbober [7]
Hope this helps you :)

8 0
2 years ago
A frog falls from its rainforest tree. If we ignore wind resistance, (a) how much time does it take the frog to fall a distance
gtnhenbr [62]

Answer:

Explanation:

a) Using the equation of motion

S = ut + 1/2gt²

S is the distance of fall

g is the acceleration due to gravity

t is the time taken

Given S = 12.0m, g = 9.81m/s^2, un= 0m/s

12 = 0+1/2(9.81)t²

12 = 4.905t²²²

t² = 12/4.905

t² = 2.446

t = √2.446

t = 1.56secs

b) To determine how fast is the frog falling at this point, we need to calculate the speed of the frog. Using the equaton v = u+gt

v = 0+9.81(1.56)

v = 15.34m/s

Hence the frog is falling at the rate of 15.34m/s

5 0
3 years ago
Virginia beach is 15 kilometers wide and 50 kilometers long. if 2 cm of rain falls on virginia beach, how many cubic meters of r
icang [17]
Assume that the shape of Virginia beach is rectangular.

Note that
1 km = 10³ m
1 cm = 10⁻² m

The area is
A = (15 km)*(50 km)
   = (15 x 10³ m)*(50 x 10³ m)
   = 7.5 x 10⁸ m²

Because 2 cm of rain fell, the volume is
V = (7.5 x 10⁸ m)*(2 x 10⁻² m) = 1.5 x 10⁶ m³

Answer:  1.5 x 10⁶ m³
4 0
3 years ago
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