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Mila [183]
3 years ago
11

The circles in the model represent atmospheric layers. Make each description with the correct name of each layer.

Chemistry
1 answer:
Masja [62]3 years ago
6 0

Answer:

The bottom is troposhere the next is sratoshere,mesosphere,thermosphere then exoshere

Explanation:

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Match the term with its description.
Ilia_Sergeevich [38]

pH(D) A compound that increases the hydroxide ions (OH-) when it is dissolved in a solution

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3 years ago
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Cindy made tea. She started with 300 grams of water at 20 degrees Celsius. She transferred 18,000 calories to the water. What wa
Serjik [45]

Answer:

T final = 80°C

Explanation:

  • Q = mCpΔT

∴ Q = 18000 cal

∴ m H2O = 300 g

∴ Cp H2O (15°C) = 0.99795 cal/g.K ≅ 1 cal/g.K

∴ T1 = 20°C = 293 K

∴ T2 = ?

⇒ 18000 cal = (300 g)(1 cal/g.K)(T2 - 293 K)

⇒ (18000 cal)/(300 cal/K) = T2 - 293 K

⇒ T2 = 293 K + 60 K

⇒ T2 = 353 K (80°C)

8 0
3 years ago
List the substances Ar, Cl2, CH4, and CH3COOH, in order of increasing strength of intermolecular attractions. List the substance
Viefleur [7K]

Answer:

Order of increasing strength of intermolecular attraction:

CH_3COOH > Cl_2 > CH_4 > Ar

Explanation:

CH_3COOH can form hydrogen bond as H atom is attached with electronegative atom O.

Rest three, Cl_2,  CH_4,  Ar are non-polar molecules.

In non-polar molecules, van der Waal's intermolecular forces of attractions exist. Hydrogen bonding is stronger intermolecular attraction then van der Waal's intermolecular forces of attraction, hence, CH_3COOH has strongest intermolecular attractions.

Ar will have least intermolecular attraction, as it behaves almost as ideal gas and there is no intermolecular attraction exist between molecules of ideal gases.

Molecular size and mass of Cl_2 is high as compared to CH_4.

van der Waals intermolecular forces of attraction increases with increase in size.

Therefore,

Order of increasing strength of intermolecular attraction will be:

CH_3COOH > Cl_2 > CH_4 > Ar

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2 years ago
Question 3:
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E. Molarity of vinegar

i hope u get this i tried to figure it out hopefully im right 

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