The 2-mg Car Increases its

What is the wavelength (in air) of a 13.0 khz vlf radio wave?

bonufazy [111]

Since,
Speed = Frequency * WaveLength

=> WaveLength = Speed / Frequency --- (A)

Frequency = 13.0 kHz.
As the radio waves are electromagnetic waves, their speed is equals to the speed of light. Therefore,
Speed = C = $3 * 10^{8} m/ s^{2}$

Plug in the values in equation(A):

A => WaveLength = $\frac{3 * 10^{8}}{13*10^{3}}$

Ans: Wavelength = 23.077 kilometers.
-i

5 0

3 years ago

How is the concept of wind best described?

konstantin123 [22]

I believe that it is the first one just a guess tho. So don't trust me, just in case

3 0

3 years ago

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15. A locomotive moved 18.0 m [W] in a time of 6.00 s and stopped. After stopping, the

mariarad [96]

Answer:

Distance = 30m

Displacement = 6m W

Explanation:

Given the following:

Movement 1 = 18m W

Movement 2 = 12m E

Diatance is a scalar quantity with only magnitude and no direction. That is, in Calculating the distance moved by the locomotive, the direction of travel or movement of the object is not considered. It only measures the total amount of movement made during the Time of motion.

Therefore, total distance traveled equals :

Movement 1 + movement 2

18m + 12m = 30m

B) Displacement also measures the movement made by an object. However, Displacement is a vector quantity and therefore, considers both magnitude and direction of travel of the object. Therefore, it measures the overall change in position of the object from its starting position.

Therefore, Displacement of the locomotive equals:

18m W - 12m E = 6m E

3 0

3 years ago

An electric train moving at 5m/s accelerates to a speed of 8m/s in 20 seconds. Fine the distance travelled in meters during the

adelina 88 [10]

<h3>Answer: 130 meters</h3>

===================================================

Explanation:

vi = 5 and vf = 8 are the initial and final velocities respectively. The change in time is t = 20 seconds.

So,

x = 0.5*(vi + vf)*t

x = 0.5*(5+8)*20

x = 130 meters

represents the distance traveled. The first equation shown above is one of the four kinematics equations.

3 0

3 years ago

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The component of the external magnetic field along the central axis of a 18 18 turn circular coil of radius 27.0 27.0 cm decreas

madreJ [45]

Answer:

Induced current I = 0.44 A

Explanation:

given data

no of turn N = 18

radius = 27.0 cm

resistance of the coil = 4.50 Ω

time = 2.90 s

magnetic field = 1.90 T to 0.500 T

solution

we get Induced EMF that is

E = - dφ ÷ dt ..............1

E = - N × A × (B2 - B1) ÷ Δt

E = N × A × (B1 - B2) ÷ Δt

area of cross section of the coil A = π × r²

area of cross section = 3.14 × (0.27)²

area of cross section = 0.228 m²

Initial magnetic field B1 = 1.9 T

and

Final magnetic field B2 = 0.5 T

time Δt = 3.7 s

put here value and we get

E = $\frac{18 \times 0.228 \times (1.9-0.5)}{2.90}$

E = 1.98 V

and

Induced current I is express as

Induced current I = E ÷ R ................2

Induced current I = $\frac{1.98}{4.5}$

Induced current I = 0.44 A

3 0

3 years ago