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Daniel [21]
3 years ago
14

A quantity of 85.0 mL of 0.900 M HCl is mixed with 85.0 mL of 0.900 M KOH in a constant-pressure calorimeter that has a heat cap

acity of 325 J/°C. If the initial temperatures of both solutions are the same at 18.24°C, what is the final temperature of the mixed solution?
Chemistry
1 answer:
san4es73 [151]3 years ago
3 0

Answer:

There is a 1:1 neutralization reaction,  so, number of moles:

0.085 l * 0.900 mol/ L = 0.0765 mol HCL

The heat produced:  0.0765 mol * -56.2 kJ/mol = -4.229 kJ (this is the heat of neutralization)

Change in temperature:    The mass to use in the equation Q=cmT.  

4229 J / (4.186 J/gC*170 g) = 6.042 C

Add to the initial temperature:

18.24 + 6.042 = 24.29 C°

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Hemoglobin (Hb) can be viewed as having two quaternary states, a low oxygen affinity state (T), and a high oxygen affinity state
natta225 [31]
<h3><u>Answer;</u></h3>

The statements that are True are;

  • Upon binding a molecule of oxygen, Hb undergoes a conformational change that makes the binding of subsequent O2 molecules easier.
  • The conformational change induced in Hb upon binding oxygen is the result of a small movement (0.2 Å) of the iron cation in the center of heme.
  • Site-directed mutagenesis studies have indicated that the cooperativity of O2 binding in Hb is attributable to the movement of the F helix in Hb.
<h3><u>Explanation</u>;</h3>
  • Hemoglobin is a key pigment in the blood that transports oxygen gas to all the tissues in the body. It is made up of two types of chains; that is two alpha chains and two beta chains.  
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3 years ago
According to the Law of Conservation of Mass, the total
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Answer:

Always equal to the total moles of the products.

Explanation:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction equal to the mass of the reactants.

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What are the parts of the earths mantle? A) Inner core, asthensophere, lithosphere
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Answer:

B

Explanation:

The mantle is composed of the mesosphere and the asthenosphere in the upper most part and in the crust is the lithosphere

5 0
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Hydrogen gas reacts rapidly with oxygen gas in the presence of a platinum catalyst. which equation correctly represents this rea
I am Lyosha [343]

Answer:

2H₂(g) + O₂(g) → 2H₂O(g), in presence of Pt as a catalyst.

Explanation:

The reaction:

<em>2H₂(g) + O₂(g) → 2H₂O(g), in presence of Pt as a catalyst.</em>

2.0 moles of hydrogen gas react with 1.0 mole of oxygen gas to produce 2.0 moles of water vapor in presence of Pt as a catalyst.

5 0
3 years ago
Read 2 more answers
2 SO2(g) + O2(g) + 2 H2O(ℓ) −→ 2 H2SO4(ℓ)
DIA [1.3K]

Answer:

6116g

Explanation:

2SO2(g) + O2(g) + 2H2O(ℓ) −→ 2H2SO4(ℓ)

We want to find the mass in grams of SO2 that is needed to react with 1527 g of O2. First we must convert the grams of O2 to moles of O2 then to moles of SO2 and then to grams of SO2

So first lets find the molar mass of O2

The mass of oxygen according to a periodic table is 15.999

Using this the mass of O2 would be 15.999(2) = 31.988g

Next we need to identify the mole ratio of O2 to SO2

Looking at the equation for 1 mole of O2 there are two moles of SO2

Next we need to find the molar mass of SO2

Again the mass of oxygen is 15.999g and the mass of Sulfur is 32.066

So the mass of SO2 would be 15.999(2) + 32.066 = 64.064g

Now that we have found all the needed conversions :

  • 1 mol O2 = 31.988g
  • 1 mol O2 = 2 mol SO2
  • 1 mol SO2 = 64.064g

We can now use dimensional analysis to calculate the answer.

Kindly check the attached image to see the table. ( sorry if its a bit blurry )
Explanation : The conversions are used to cancel out the units to get to the final unit which is gSO2.

Once the units are cancelled out except for the gSO2 we mutliply and divide based off of what the table says to do.
Here first we divide 1527 by 31.988. We than multiply by 2. Finally we multiply by 64.064 to get the final answer which is 6116gSO2

7 0
2 years ago
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