Question

At STP, what is the volume of 55.0 g of BF3?

Answer 1

Answer:

The volume of 55 grams of BF₃ is 18.1664 L.

Explanation:

If the molar mass of compound BF₃ is 67.81 $\frac{grams}{mole}$, then the number of moles 55 grams of compound contains is calculated as:

$55 grams* \frac{1 mole}{67.81 grams} = 0.811 moles$

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

Then it is possible to apply the following rule of three: if by definition of STP 1 mole of a compound occupies 22.4 L, 0.811 moles of the compound occupies how much volume?

$volume=\frac{0.811 moles* 22.4 L}{1 mole}$

volume= 18.1664 L

The volume of 55 grams of BF₃ is 18.1664 L.