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AnnyKZ [126]
3 years ago
8

How many moles are in 17.0 grams of H2O2?

Chemistry
2 answers:
Dvinal [7]3 years ago
8 0

Answer:

C) 0.500 mol H2O2 is correct

Explanation:

I just took the test and got it right ;)

vekshin13 years ago
3 0

Answer: Option (c) is the correct answer.

Explanation:

Number of moles is defined as given mass of substance divided by molar mass.

Mathematically,    No. of moles = \frac{mass of given substance}{molar mass}

Molar mass of H_{2}O_{2} is 34.015 g/mol.

Therefore, calculate number of moles of H_{2}O_{2} as follows.

       No. of moles = \frac{mass of given substance}{molar mass}

                             = \frac{17.0 g}{34.015 g/mol}

                             = 0.4997 mol

or,                          = 0.500 mol (approx)

Thus, we can conclude that 0.500 mol is present in 17.0 grams of H_{2}O_{2}.

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<h3>What is specific heat capacity?</h3>

The specific heat capacity is the property of a substance that shows how much its temperature changes when it is exposed to heat.

Thus, the  properties which keep the water temperature from changing much are;

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E.) the iron nail's high specific heat capacity

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2 years ago
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6 0
3 years ago
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marin [14]

The concentration of [H3O⁺]=2.86 x 10⁻⁶ M

<h3>Further explanation</h3>

In general, the weak acid ionization reaction  

HA (aq) ---> H⁺ (aq) + A⁻ (aq)  

Ka's value  

\large {\boxed {\bold {Ka \: = \: \frac {[H ^ +] [A ^ -]} {[HA]}}}}

Reaction

HC₂H₃O₂ (aq) + H₂O (l) ⇔  (aq) + H₃O⁺ (aq) Ka = 1.8 x 10⁻⁵

\tt Ka=\dfrac{[C_2H_3O^{2-}[H_3O^+]]}{[HC_2H_3O_2]}}\\\\1.8\times 10^{-5}=\dfrac{0.22\times [H_3O^+]}{0.035}

[H₃O⁺]=2.86 x 10⁻⁶ M

5 0
3 years ago
Question 116 g of sunflower oil is
Luba_88 [7]
<h2>Answer:  125.41 mL</h2>

Explanation:

Volume = mass ÷ density

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<h3>A 116 g of sunflower oil of 0.925 g/mL has a volume of 125.41 mL.</h3>
7 0
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