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kirza4 [7]
2 years ago
12

Balance FeCl3 + MgO ---> Fe2O3 + MgCl2

Chemistry
1 answer:
german2 years ago
3 0

Answer: The balanced equation is 2FeCl_{3} + 3MgO \rightarrow Fe_{2}O_{3} + 3MgCl_{2}

Explanation:

The given reaction equation is as follows.

FeCl_{3} + MgO \rightarrow Fe_{2}O_{3} + MgCl_{2}

Here, number of atoms present on reactant side are as follows.

  • Fe = 1
  • Cl = 3
  • Mg = 1
  • O = 1

Number of atoms on product side are as follows.

  • Fe = 2
  • Cl = 2
  • Mg = 1
  • O = 3

To balance this equation, multiply FeCl_{3} by 2 and MgO by 3 on reactant side. Also, multiply MgCl_{2} by 3 on product side. Therefore, the equation can be rewritten as follows.

2FeCl_{3} + 3MgO \rightarrow Fe_{2}O_{3} + 3MgCl_{2}

Hence, number of atoms on reactant side are as follows.

  • Fe = 2
  • Cl = 6
  • Mg = 3
  • O = 3

Number of atoms on product side are as follows.

  • Fe = 2
  • Cl = 6
  • Mg = 3
  • O = 3

Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.

Thus, we can conclude that the balanced equation is 2FeCl_{3} + 3MgO \rightarrow Fe_{2}O_{3} + 3MgCl_{2}.

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Use the equation to determine what mass of FeS must react to form 326 g of FeCl2.
iogann1982 [59]

Answer:

We need 226 grams of FeS

Explanation:

Step 1: Data given

Mass of FeCl2 = 326 grams

Molar mass FeCl2 = 126.75 g/mol

Step 2: The balanced equation

FeS + 2 HCl → H2S + FeCl2

Step 3: Calculate moles FeCl2

Moles FeCl2 = 326 grams / 126.75 grams

Moles FeCl2 = 2.57 moles

Step 4: Calculate moles FeS needed

For 1 mol H2S and 1 mol FeCl2 produced, we need 1 mol FeS and 2 moles HCl

For 2.57 moles FeCl2 we need 2.57 moles FeS

Step 5: Calculate mass FeS

Mass FeS = 2.57 moles * 87.92 g/mol

Mass FeS = 226 grams FeS

We need 226 grams of FeS

4 0
3 years ago
If 42.8 mL of 0.204 M HCl solution is needed to neutralize a solution of Ca(OH)2, how many grams of Ca(OH)2 must be in the solut
Aneli [31]

Hey There!

At neutralisation moles of H⁺ from HCl  = moles of OH⁻ from Ca(OH)2  so :

0.204 * 42.8 / 1000  => 0.0087312 moles

Moles of Ca(OH)2 :

2 HCl + Ca(OH)2 = CaCl2 + 2 H2O

0.0087312 / 2 => 0.0043656 moles (  since each Ca(OH)2 ives 2 OH⁻ ions )

Therefore:

Molar mass Ca(OH)2 = 74.1 g/mol

mass = moles of Ca(OH)2 * molar mass

mass =  0.0043656 * 74.1

mass = 0.32 g of Ca(OH)2


Hope that helps!

6 0
3 years ago
A chemist weighed out 19.9 g of aluminum. Calculate the number of moles of aluminum she weighed out.
vodomira [7]
Aluminum is 26.982 grams per mole, so 26.982/19.9 will give you the moles 1.3558794
3 0
3 years ago
PLEASE HELP!!!<br><br><br><br> How many grams are in 10.11 moles of sucrose?
Sloan [31]
There would be 67 left because you do
5 0
2 years ago
according to Boyles law if the initial pressure and volume of a gas were five atm for the pressure and 10 mL for the volume and
maks197457 [2]

Answer:The new volume is 5mL

Explanation:

The formular for Boyles Law is; P1 V1 = P2 V2

Where P1 = 1st Pressure   V1 = First Volume

          P2 = 2nd Pressure V2 = Second Volume

From the question; P1 = 5atm, V1 = 10ml

                                P2 = 2 x P1 (2 x 5) = 10 atm   V2 =?  

Using the Boyles Law Formular;  P1 V1 = P2 V2, we make V2 the subject of formular;  P1 V1/ P2 = V2

∴ 5 x 10/ 10 = 5

∴ V2 = 5mL

5 0
3 years ago
Read 2 more answers
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