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kirza4 [7]
3 years ago
12

Balance FeCl3 + MgO ---> Fe2O3 + MgCl2

Chemistry
1 answer:
german3 years ago
3 0

Answer: The balanced equation is 2FeCl_{3} + 3MgO \rightarrow Fe_{2}O_{3} + 3MgCl_{2}

Explanation:

The given reaction equation is as follows.

FeCl_{3} + MgO \rightarrow Fe_{2}O_{3} + MgCl_{2}

Here, number of atoms present on reactant side are as follows.

  • Fe = 1
  • Cl = 3
  • Mg = 1
  • O = 1

Number of atoms on product side are as follows.

  • Fe = 2
  • Cl = 2
  • Mg = 1
  • O = 3

To balance this equation, multiply FeCl_{3} by 2 and MgO by 3 on reactant side. Also, multiply MgCl_{2} by 3 on product side. Therefore, the equation can be rewritten as follows.

2FeCl_{3} + 3MgO \rightarrow Fe_{2}O_{3} + 3MgCl_{2}

Hence, number of atoms on reactant side are as follows.

  • Fe = 2
  • Cl = 6
  • Mg = 3
  • O = 3

Number of atoms on product side are as follows.

  • Fe = 2
  • Cl = 6
  • Mg = 3
  • O = 3

Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.

Thus, we can conclude that the balanced equation is 2FeCl_{3} + 3MgO \rightarrow Fe_{2}O_{3} + 3MgCl_{2}.

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<h3>1</h3>

Species shown in bold are precipitates.

  • Ca(NO₃)₂ + 2 KOH → Ca(OH)₂ + 2 KNO₃
  • Ca(NO₃)₂ + Na₂C₂O₄ → CaC₂O₄ + 2 NaNO₃
  • Cu(NO₃)₂ + 2 KI → CuI₂ + 2 KI
  • Cu(NO₃)₂ + 2 KOH → Cu(OH)₂ + 2 KNO₃
  • Cu(NO₃)₂ + Na₂C₂O₄ → CuC₂O₄ + 2 NaNO₃
  • Ni(NO₃)₂ + 2 KOH → Ni(OH)₂ + 2 KNO₃
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  • Zn(NO₃)₂ + 2 KOH → Zn(OH)₂ + 2 KNO₃
  • Zn(NO₃)₂ + Na₂C₂O₄ → ZnC₂O₄ + 2 NaNO₃

<h3>2</h3>

A double replacement reaction takes place only if it reduces in the concentration of ions in the solution. For example, the reaction between Ca(NO₃)₂ and KOH produces Ca(OH)₂. Ca(OH)₂ barely dissolves. The reaction has removed Ca²⁺ and OH⁻ ions from the solution.

Some of the reactions lead to neither precipitates nor gases. They will not take place since they are not energetically favored.


<h3>3</h3>

Compare the first and last row:

Both Ca(NO₃)₂ and Zn(NO₃)₂ react with KOH. However, between the two precipitates formed, Ca(OH)₂ is more soluble than Zn(OH)₂.

As a result, add the same amount of KOH to two Ca(NO₃)₂ and Zn(NO₃)₂ of equal concentration. The solution that end up with more precipitate shall belong to Zn(NO₃)₂.


<h3>4</h3>

Compare the second and third row:

Cu(NO₃)₂ reacts with KI, but Ni(NO₃)₂ does not. Thus, add equal amount of KI to the two unknowns. The solution that forms precipitate shall belong to Cu(NO₃)₂.

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