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3 years ago

What is the answer to this question?

Chemistry

2 answers:

rodikova [14]3 years ago

7 0

Answer:

Vertebrae

Explanation:

Vertebrae are the 33 individual bones that interlock with each other to form the spinal column. The vertebrae are numbered and divided into regions: cervical, thoracic, lumbar, sacrum, and coccyx (Fig. 2). Only the top 24 bones are moveable; the vertebrae of the sacrum and coccyx are fused.

mash [69]3 years ago

7 0

I believe the answer is vertebrae. There are 24 bones stacked up on each other that make up your backbone.

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Anyone know the answer to this one?

sergey [27]

Answer:

C) 0.24 M

Explanation:

The given chemical reaction is presented as follows;

H₂SO₄(aq) + 2 KOH(aq) → K₂SO₄(aq) + 2 H₂O(l)

The titration experiment results are;

Volume of H₂SO₄(aq) used = 12.0 mL

Volume of KOH (aq) used = 36.0 mL

Concentration of KOH (aq) = 0.16 M

The number of moles of KOH present, n = 0.16 M × 36/1000 = 0.00576 moles

From the given reaction, 1 mole of H₂SO₄ reacts with 2 moles of KOH to give 1 mole of K₂SO₄ and 2 moles of H₂O

Therefore, 0.00576 moles of KOH reacts with (1/2) × 0.00576 moles = 0.00288 moles of H₂SO₄

Therefore, for the reaction;

The number of moles of H₂SO₄ in 12.0 mL of H₂SO₄ = 0.00288 moles

The concentration of the H₂SO₄ = 0.00288 M/(12.0 mL) = 0.24 M

The concentration of H₂SO₄ in the reaction = 0.24 M.

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3 years ago

All of the elements below can exist as network solids EXCEPT 1. As 2. B 3. Si 4. O 5. C

Olin [163]

Answer:

4. Oxygen

Explanation:

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3 years ago

A compound is 40.0 % C, 53.3 % 0, and 6.66 % H What is its molecular formula if its molecular mass is 60 g? Show all your work

Ksenya-84 [330]

The molecular mass 58%

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3 years ago

How did qualitative chemical and enzyme tests help avery identify dna as the transforming principle?

Rzqust [24]

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4 years ago

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How to balance lead and silver acetate yields lead (||) acetate and silver

arsen [322]

The given elements put into an equation using their symbols are as follows:
Pb + $AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb + $AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb + $2AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb + $2AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + 2Ag

That is your final equation

The coefficients are 2 + 2 = 1 + 2

3 0

3 years ago

What is the answer to this question?​

What is the answer to this question?