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gulaghasi [49]
3 years ago
13

How much force required to prevent a book from falling if the mass of the book is 50 grams?

Physics
1 answer:
romanna [79]3 years ago
6 0

Answer:

The gravitational force on a mass is its weight. We can write this in vector form, where  

→

w

is weight and m is mass, as

→

w

=

m

→

g

.

In scalar form, we can write

w

=

m

g

.

Since  

g

=

9.80

m/s

2

on Earth, the weight of a 1.00-kg object on Earth is 9.80 N:

w

=

m

g

=

(

1.00

kg

)

(

9.80

m/s

2

)

=

9.80

N

Explanation:

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The naked eye cannot see the corona of the sun because the photosphere' is light is much to bright. When we look at the sun, we are virtually not even looking at it. We only see the photosphere.
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5 0
3 years ago
Read 2 more answers
if you have a 1.5 L container of tea and the label state that the container contains 1.2 g of sugar grams of sugar what's the co
astraxan [27]

Given data

mass of solute (m) = 1.2 g ,

Volume of solution  = 1.5 L ,

                                 = 1.5 × 1000 mL

                                 = 1500 mL ,

What is the concentration of solution = ?

                                 concentration = (mass of solute) ÷ (100 mL of solution)

                                                         = (1.2) ÷ (1500 mL of solution)

<em> Note: </em><em> remember to divide both numerator and denominator by 15 to get concentration per 100 ml</em>

<em>                     Therefore concentration  = 0.1 /100 mL ;</em>

<em>The concentration of sugar in a tea is  0.1/100 mL</em>

3 0
4 years ago
A soccer ball is at rest. A player kicks the ball from the ground. What impact will the energy transfer have on the ball?
stepladder [879]

Answer:

Its B

Explanation:

the force of the ball is being kicked from the back side of the ball will causes a pushing motion and the ball will move forward

8 0
3 years ago
Read 2 more answers
an 80 kg cart goes around the inside of a vertical loop of a roller coaster. the radius of the loop is 5m and the cart moves at
GarryVolchara [31]

Answer:

F=  224 N

Explanation:

Given that

mass ,m = 80 kg

Radius ,r= 5 m

speed at the top v= 8 m/s

The force at the top = F

Now by using the Second law of Newton's

F+mg=\dfrac{mv^2}{r}

Now by putting the values

F+80\times 10 = \dfrac{80\times 8^}{5}

Take  g = 10 m/s²

F= \dfrac{80\times 8^2}{5}-800

F=  224 N

Therefore the force exerted by the track at the top position will be 224 N.

3 0
4 years ago
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