1.2*10^24# atoms of chlorine
Explanation:
Chlorine gas (#Cl_2#) has two atoms of elemental chlorine in a molecule, so:
#1# mol of #Cl_2# have #6*10^23# molecules of #Cl_2#
#1# molecule of #Cl_2# have #2# atoms per molucule
Then #2*6*10^23 = 1.2*10^24# atoms of chlorine in a mol of chlorine gas
The Answer should be A Light particle
0.3268 moles of PC15 can be produced from 58.0 g of Cl₂ (and excess
P4)
<h3>How to calculate moles?</h3>
The balanced chemical equation is

The mass of clorine is m(
) = 58.0 g
The amount of clorine is n(
) = m(
)/M(
) = 58/70.906 = 0.817 mol
The stoichiometric reaction,shows that
10 moles of
yield 4 moles of
;
0.817 of
yield x moles of 
n(
) = 4*0.817/10 = 0.3268 mol
To know more about stoichiometric reaction, refer:
brainly.com/question/14935523
#SPJ9
Answer:
I'm pretty sure the answer is B.
Explanation:
I hope this helps
Answer:
to talk in a way that the class can all understand . help them in thing they are falling . and have a good relashaship.
Explanation: