Answer:
a) CI = ( 5,1 ; 5,7 )
b) SE = 0,1
Step-by-step explanation:
a) Sample random n = 100
Mean = μ = 5,4
Standard deviation s = 1,3
CI = 99 % α = 1 % α = 0,01 α/2 = 0,005
z(c) for 0,005 is from z-table z(c) = 2,575
z(c) = ( X - μ ) /s/√n CI = μ ± z(c) * s/√n
CI = 5,4 ± 2,575* 1,3/10
CI = 5,4 ± 0,334
CI = ( 5,1 ; 5,7 )
b) SE = Standard deviation / √n
SE = 1,3 /10 SE = 0,1
We can support that with 99 % of probability our random variable will be in the CI.
Answer:
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Step-by-step explanation:
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Answer:
The value of y is -5
Step-by-step explanation:
we have
------> equation A
------> equation B
we know that
If x and y satisfy both equations, then (x,y) is the solution of the system of equations
Using a graphing tool
Remember that
The solution of the systems of equations is the intersection point both graphs
The intersection point is (2,-5)
therefore
The solution of the system of equations is the point (2,-5)
The value of y is -5