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MAXImum [283]
3 years ago
6

Because of the curvature of the earth, the maximum distance D that you can see from the top of a tall building of height h is es

timated by the formula D = 2rh + h2 where r = 3960 mi is the radius of the earth and D and h are also measured in miles. How far can you see from the observation deck of a tall building, 1100 ft above the ground? (Round your answer to one decimal place.)
Physics
1 answer:
mojhsa [17]3 years ago
8 0

Answer:

 D = 9.9 10⁶ mi

Explanation:

In the exercise they give the expression for maximum viewing distance

       D = 2 r h + h²

Ask for this distance for a height of 1100 feet

Let's calculate

        D = 2 3960 1100 + 1100²

        D = 8.712 10⁶ + 1.21 10⁶

        D = 9.92 10⁶ mi

         D = 9.9 10⁶ mi

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Asteroid Ida was photographed by the Galileo spacecraft in 1993, and the photograph revealed that the asteroid has a small moon,
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Answer:

The orbital speed of Dactyl is 5.55m/s

Explanation:

The orbital speed can be determined by the combination of the universal law of gravity and Newton's second law:

F = G\frac{M \cdot m}{r^{2}}  (1)

Where G is gravitational constant, M is the mass of the asteroid, m is the mass of the moon and r is the distance between them

In the other hand, Newton's second law can be defined as:

F = ma  (2)

Where m is the mass and a is the acceleration

Then, equation 2 can be replaced in equation 1

m\cdot a  = G\frac{M \cdot m}{r^{2}}  (2)

However, a will be the centripetal acceleration since the moon Dactyl describe a circular motion around the asteroid

a = \frac{v^{2}}{r}  (3)

m\frac{v^{2}}{r} = G\frac{M \cdot m}{r^{2}} (4)

Therefore, v can be isolated from equation 4:

m \cdot v^{2} = G \frac{M \cdot m}{r^{2}}r

m \cdot v^{2} = G \frac{M \cdot m}{r}

v^{2} = G \frac{M \cdot m}{rm}

v^{2} = G \frac{M}{r}

v = \sqrt{\frac{G M}{r}} (5)

Finally, the orbital speed can be found from equation 5:

Notice, that it is necessary to express r in units of meters.

r = 95km \cdot \frac{1000m}{1km} ⇒ 95000m

v = \sqrt{\frac{(6.672x10^{-11}N.m^{2}/kg^{2})(4.4x10^{16}kg)}{95000m}}

v = 5.55m/s

Hence, the orbital speed of Dactyl is 5.55m/s

3 0
2 years ago
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Answer:D 1.7

Explanation:

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Answer:

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