If B is the midpoint of AC, AB = 8x + 5, and BC = 5x2 - 16, then find x and AC
1 answer:
Answer:
Step-by-step explanation:
AB = 8x + 5
BC = 5x² - 16
5x² - 16 = 8x + 5
5x² - 8x - 21 = 0
Quadratic formula
x = [8 ± √(8² – 4·5(-21))] / [2·5]
= [8 ± √484] / 10
= [8 ± 22] /10
= -1.4, 3
-1.4 is an extraneous solution.
x = 3
AB = 8x+5 = 29
AC = 58
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