Answer:
O lies on the perpendicular bisector of AB. ... Then, O' will lie on the perpendicular bisector PQ and RS. We know that, two lines cannot intersect at more than one point, So O' must coincide with O. Hence, there is one and only one circle passing through three non collinear points
Step-by-step explanation:
Answer:
shaded area = 113.64 cm²
Step-by-step explanation:
To find the shaded area, subtract the area of the circle from the area of the triangle.
Area of a triangle = 1/2 x base x height
⇒ area of triangle = 1/2 x 25 x 21.4 = 267.5 cm²
Area of a circle = 
(where r is the radius)
From inspection, we can see that the diameter of the circle = 14 cm
Therefore, as the diameter = 2r, then r = 14 ÷ 2 = 7 cm
⇒ area of circle = 3.14 x 7² = 153.86 cm²
Shaded area = area of triangle - area of circle
⇒ shaded area = 267.5 - 153.86 = 113.64 cm²
Answer:of sorry but not gunna do all that or is it just a lil bit tell me
Step-by-step explanation:
Answer:
Let's use these two sets given to explain what is the domain.
Each value from the left set is x, and from the right is f(x).
If we plug any x from the left set in the function, we'll get f(x) that corresponds to it and that's exactly what the arrows are showing.
Domain of the function is, basically, a set of all values x can have.
In this case, it's easy to see, those are all members of the left set (-6, 1, 5, 8), but sometimes this set can have lots and lots of members, even infinity.
