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Airida [17]
3 years ago
11

Predict whether the entropy change for this process is positive or negative and explain your answer. Then, predict whether the f

ree energy change for the process is positive or negative and explain your answer.
Chemistry
1 answer:
andrew11 [14]3 years ago
7 0

The given question is incomplete. The complete question is:

Consider the spontaneous dissolution of NaCl in water: NaCl(s) → Na+(aq) + Cl −(aq) Predict whether the entropy change for this process is positive or negative and explain your answer. Then, predict whether the free energy change for the process is positive or negative and explain your answer.

Answer: The entropy change is positive. The free energy change for the process is negative and reaction is spontaneous.

Explanation:

Entropy is defined as the degree of randomness of a system. For a system in which randomness increses , the enetropy is said to increase and \Delta S is positive.

As in the given reaction : NaCl(s)\rightarrow Na^+(aq)+Cl^-(aq) , the solid is dissociating to give ions , randomness increases and thus entropy is positive.

Also the dissociation of a molecule requires energy , thus the enthalpy \Delta H is also positive as heat is absorbed by the system.

\Delta G=\Delta H-T\Delta S

\Delta G=(+ve)-T(+ve)

\Delta G=-ve when Temperature is high.

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When a monatomic ideal gas expands at a constant pressure of 6.4 x 105 Pa, the volume of the gas increases by 3.2 x 10-3 m3. Det
defon

Answer:

5118.50 J

Explanation:

pΔv=nRΔT ;

therefore, ΔT=PV/nR

ΔT = (6.4×10^5)(3.2×10^(-3)/1×8.314

ΔT= 2.4633×10^2 = 246.33 K

specific heat at constant pressure is given as:

c_p = 3/2R

c_p = 12.5 J/mol K

Now, substitute in equation (1)

we know that

Q=ΔU+W ;

and

W=pΔV= 6.4×10^5×3.2×10^(-3) = 2048 J

now

ΔU=CvΔT = 12.465×246.33 =3070.50 J ;

therefore  

Q=3070.50+2048= 5118.50 J

4 0
3 years ago
An aqueous solution is saturated with both a solid and a gas at 5 ∘c. what is likely to happen if the solution is heated to 85 ∘
denpristay [2]
<span>When the aqueous solution is heated to 85âC, the gas entrapped in the aqueous solution is released since the vapour pressure of the particular entrapped gas is more than the solution. The solid saturated in the aqueous solution returns back to its original form once the aqueous solution evaporates. A good example is that of the salt left behind after heating a brine solution to evaporate.</span>
4 0
4 years ago
Can you tell me answe of all (5,6,7,8) ​
GREYUIT [131]

Answer:

i dont know thank you soo much

4 0
1 year ago
4. Your mission, if you choose to accept it, is to make 10mmol/L acetate buffer, pH5.0. Beginning with 10mmol/L HAc, what concen
julia-pushkina [17]

Answer:

6,45mmol/L of NaOH you need to add to reach this pH.

Explanation:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ <em>pka = 4,74</em>

Henderson-Hasselbalch equation for acetate buffer is:

5,0 = 4,74 + log₁₀\frac{[CH_{3}COO^-]}{[CH_{3}COOH]}

Solving:

1,82 = \frac{[CH_{3}COO^-]}{[CH_{3}COOH]} <em>(1)</em>

As total concentration of acetate buffer is:

10 mM = [CH₃COOH] + [CH₃COO⁻] <em>(2)</em>

Replacing (2) in (1)

<em>[CH₃COOH] = 3,55 mM</em>

And

<em>[CH₃COO⁻] = 6,45 mM</em>

Knowing that:

<em>CH₃COOH + NaOH → CH₃COO⁻ + Na⁺ + H₂O</em>

Having in the first 10mmol/L of CH₃COOH, you need to add <em>6,45 mmol/L of NaOH. </em>to obtain in the last 6,45mmol/L of CH₃COO⁻ and 3,55mmol/L of CH₃<em>COOH </em>.

I hope it helps!

7 0
3 years ago
Calculate how many moles are in 63.1 grams FeCl3.
Lynna [10]

Answer: 1 grams FeCl3 = 0.0061650760770388 mole using the molecular weight calculator and the molar mass of FeCl3.

Explanation:

8 0
3 years ago
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