Li₂O
Explanation:
Elements or ions exchange their combining powers or their simplest whole number ratio during the formation of a chemical formulae of compounds.
The combining power of lithium is 1
Oxygen is 2
Lithium Oxygen
Combining
power 1 2
Exchange of
valencies 2 1
Molecular formula of the compound gives Li₂O
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Molecular formula brainly.com/question/5537295
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The balanced chemical reaction is given as follows:
<span>2 KClO3(s) → 2 KCl(s) + 3 O2(g)
The starting amount of the reactant are given above. These values would be used for the calculations. We do as follows:
</span>2.72 g KClO3 (1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 1.06 g O2
<span>
0.361 g KClO3 </span>(1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 0.14 g O2
<span>
83.6 kg KClO3 (1000g / 1kg) </span>(1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 3275.76 g O2
<span>
22.5 mg KClO3</span> (1 g / 1000 mg) (1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 0.009 g O2
<h2>‘ <u>Refer </u><u>the </u><u>attachment</u><u> </u><u>’</u></h2>
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To determine this all you would need to do is rearrange the equation for density and solve for the value of volume. Then plug in the numerical values into the equation and solve for v.
D = m/v
Dv = m
V = m/D
V = 15.7 g/2.50 g/cm^3.
V = 6.28 ml.
