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kondor19780726 [428]
2 years ago
15

3rd law of thermodynamics.. 2 Different Examples((Thnks))

Chemistry
1 answer:
VLD [36.1K]2 years ago
5 0

Answer:

See explanation

Explanation:

The third law of thermodynamics states that "the entropy of a perfect crystal of a pure substance approaches zero as the temperature approaches zero" (Wikipedia).

One example of the third law of thermodynamics has to do with steam. Steam is gaseous water. Since it is a gas, its molecules are free to move around therefore its entropy is high. When the temperature of the steam is decreased below 100 degrees, the molecules of steam loose energy and turn into liquid water and do not move as freely as they did in the gaseous state. If the temperature is further decreased to yield ice at zero degrees, the molecules of water are "frozen" in their positions and the entropy of the system decreases to zero.

Also, the ions in ionic crystal solids move around when the substance is in solution or in molten state hence the substance conducts electricity. When the ionic substance is in solid state, the ions do not move about and the entropy of the solid system tends towards zero.

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galina1969 [7]
Answer:
Molarity = 2.3 M

Explanation:
Molarity can be calculated using the following rule:
Molarity = number of moles of solute / volume of solution

1- getting the number of moles:
We are given that:
mass of solute = 105.96 grams
From the periodic table:
atomic mass of carbon = 12 grams
atomic mass of hydrogen = 1 gram
atomic mass of oxygen = 16 grams
Therefore:
molar mass of C2H6O = 2(12) + 6(1) + 16 = 46 grams
Now, we can get the number of moles as follows:
number of moles = mass / molar mass = 105.96 / 46 = 2.3 moles

2- The volume of solution is given = 1 liter

3- getting the molarity:
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molarity = 2.3 / 1
molarity = 2.3 M

Hope this helps :)
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Explanation:

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