What is the balanced chemical equation for the reaction of sodium and oxygen?Na + O to NaO2Na + O2 to 2 NaO4Na + O2 to 2Na2ONa +
1 answer:
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Answer:
A. 96.3 mg/dL
Absolute error: 5.7 mg/dL
Relative error: 5.6%
B. 97.2 mg/dL
Absolute error: 4.8 mg/dL
Relative error: 4.7%
C. 104.8 mg/dL
Absolute error: 2.8 mg/dL
Relative error: 2.7%
D. 111.5 mg/dL
Absolute error: 9.5 mg/dL
Relative error: 9.3%
E. 110.5 mg/dL
Absolute error: 8.5 mg/dL
Relative error: 8.3%
Explanation:
The formula for the absolute error is:
Absolute error = |Actual Value - Measured Value|
The formula for the relative error is:
Relative error = |Absolute error/Actual value|
In your exercise, we have that
Actual Value = 102.0 mg/dL
A. 96.3 mg/dL:
B. 97.2 mg/dL
C. 104.8 mg/dL
D. 111.5 mg/dL
E. 110.5 mg/dL
Answer:
The value of of the an ethylamine is
.
Explanation:
The pH of the solution = 12.067
The pOH of the solution = 14 - pH =14-12.607 =1.933
Initially
0.342 M 0 0
At equilibrium
(0.342-x) x x
The value of x =
The expression of is given as:
The value of of the an ethylamine is
.