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atroni [7]
1 year ago
5

What is the balanced chemical equation for the reaction of sodium and oxygen?Na + O to NaO2Na + O2 to 2 NaO4Na + O2 to 2Na2ONa +

O2 to NaO2
Chemistry
1 answer:
zavuch27 [327]1 year ago
6 0

Answer

4Na + O₂ → 2Na₂O

Explanation

Sodium reacts with oxygen to form sodium oxide and has the following balanced chemical equation:

4Na + O₂ → 2Na₂O.

Hence, the balanced chemical equation for the reaction of sodium and oxygen is:

4Na + O2 to 2Na2O

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A helium balloon with an internal pressure of 1atm and a volume of 4.20 L at 18.0°C is released. What volume will the balloon oc
kari74 [83]

Answer:

7.59 L

Explanation:

- Use combined gas law formula and rearrange.

- Change C to K

- Hope that helped! Please let me know if you need further explanation.

3 0
2 years ago
What is true about ionic compounds?
bezimeni [28]
It’s D I am pretty sure.
6 0
3 years ago
Butanol is composed of carbon, hydrogen, and oxygen. If 1.0 mol of butanol contains 6.0 x 1024 atoms of hydrogen, what is the su
yanalaym [24]

Answer:

Option B. 10

Explanation:

If 1 mol of butanol contains 6×10²⁴ atoms of H, let's calculate the amount of H.

(number of atoms  / NA)

6.02 x 10²³ atoms ___ 1 mol

6×10²⁴ atoms will occupy (6×10²⁴ / NA) = 9.96 moles

H, has 10 moles in the butano formula.

4 0
3 years ago
An ideal gas sealed in a rigid 4.86-L cylinder, initially at pressure Pi=10.90 atm, is cooled until the pressure in the cylinder
seraphim [82]

Answer:

\Delta H=-11897J

Explanation:

Hello,

In this case, it is widely known that for isochoric processes, the change in the enthalpy is computed by:

\Delta H=\Delta U+V\Delta P

Whereas the change in the internal energy is computed by:

\Delta U=nCv\Delta T

So we compute the initial and final temperatures for one mole of the ideal gas:

T_1= \frac{P_1V}{nR}=\frac{10.90atm*4.86L}{0.082*n}=\frac{646.02K  }{n} \\\\T_2= \frac{P_2V}{nR}=\frac{1.24atm*4.86L}{0.082*n}=\frac{73.49K  }{n}

Next, the change in the internal energy, since the volume-constant specific heat could be assumed as ³/₂R:

\Delta U=1mol*\frac{3}{2} (8.314\frac{J}{mol*K} )*(73.49K-646.02K )=-7140J

Then, the volume-pressure product in Joules:

V\Delta P=4.86L*\frac{1m^3}{1000L} *(1.24atm-10.90atm)*\frac{101325Pa}{1atm} \\\\V\Delta P=-4756.96J

Finally, the change in the enthalpy for the process:

\Delta H=-7140J-4757J\\\\\Delta H=-11897J

Best regards.

7 0
3 years ago
Read the list of
Ksenya-84 [330]
Answer
B I’m pretty sure
Explanation
6 0
2 years ago
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