Answer:
- the specific gravity of the block is 0.75
- the specific gravity of the solution is 1.5
Explanation:
Given the data in the question;
first we find the specific gravity of a block SGB
SGB = ( block vol below / total block vol ) × the specific gravity of water
we substitute
SG
= ( 1.5 / (1.5 + 0.5 ) ) × 1
SG
= ( 1.5 / (1.5 + 0.5 ) ) × 1
SG
= (1.5 / 2) × 1
SG
= 0.75
Therefore, the specific gravity of the block is 0.75
specific gravity of solution SG
SG
= (total block vol / block below ) × SG
we substitute
SG
= ( 2 / 1 ) × 0.75
SG
= 2 × 0.75
SG
= 1.5
Therefore, the specific gravity of the solution is 1.5
In this problem, Charles' law is applicable since constant pressure with varying volume and temperature are given. Charles' law derived from ideal gas law is expressed as

. Subsituting V1=556 cm3, T1=278 K and T2=231 K, V2 or the new volume is 462 cm3.
Answer:
2 moles
Explanation:
In one mole of sulfuric acid
There is 2 moles of hydrogen
4 moles of oxygen
and 1 mole of sulfur.
Using oil as energy
Hope this helps!:)