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aalyn [17]
3 years ago
13

Isotopes called what are used to diagnose disease and to study environmental conditions

Chemistry
1 answer:
Ksivusya [100]3 years ago
7 0
A radioactive tracer, I believe. Someone check that lol.
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How does Elnora feel about her future? A) She takes one day at a time. B) She is apprehensive and anxious. C) She is optimistic
Georgia [21]

Answer:

D) she is confident and has already made plans

4 0
3 years ago
What is the mass prevent of manganese (mn) in potassium permanganate (KMnO4)​
oksian1 [2.3K]

Answer:

               Mass percent of Mn is 34.76 %

Explanation:

                    <em>Mass percent</em> of an element is the mass of that element divided by the total mass of the elements forming that compound (or molecular mass.

So,

Mass percent of Mn will be given as,

          %Mn  =  Atomic Mass of Mn / Molecular Mass of KMnO₄ × 100

So,

Atomic Mass of Mn  =  54.94 g/mol

Molecular Mass of KMnO4  =  158.034 g/mol

Putting values in above formula,

          %Mn  =  54.94 g/mol ÷ 158.034 g/mol × 100

          %Mn  = 34.76 %

4 0
4 years ago
Calculate the ph of a 0.60 m h2so3, solution that has the stepwise dissociation constants ka1 = 1.5 × 10-2 and 1.82 1.06 1.02 2.
Vsevolod [243]
Missing in your question Ka2 =6.3x10^-8
From this reaction:
 H2SO3 + H2O ↔ H3O+  + HSO3-
by using the ICE table :
                H2SO3     ↔    H3O     +    HSO3- 
intial         0.6                     0                  0
change     -X                      +X                +X
Equ         (0.6-X)                  X                   X

when Ka1 = [H3O+][HSO3-]/[H2SO3]
So by substitution:
1.5X10^-2 = (X*X) / (0.6-X) by solving this equation for X
∴ X = 0.088
∴[H2SO3] = 0.6 - 0.088 = 0.512
[HSO3-] = [H3O+] = 0.088

by using the ICE table 2:
                 HSO3-     ↔   H3O     +     SO3-
initial        0.088              0.088              0
change    -X                      +X                   +X
Equ         (0.088-X)          (0.088+X)          X

Ka2= [H3O+] [SO3-] / [HSO3-]
we can assume [HSO3-] =  0.088 as the value of Ka2 is very small
 6.3x10^-8 = (0.088+X)*X / 0.088
X^2 +0.088 X - 5.5x10^-9= 0 by solving this equation for X
∴X= 6.3x10^-8
∴[H3O+] = 0.088 + 6.3x10^-8
               = 0.088 m ( because X is so small)
∴PH= -㏒[H3O+]
       = -㏒ 0.088 = 1.06 
5 0
3 years ago
Read 2 more answers
What is an example of a soultion
Marrrta [24]

Answer:

Did you mean solution??

In chemistry, a solution is considered as a special type of homogeneous mixture composed of two or more substances. In such a mixture, a solute is a substance dissolved in another substance, known as a solvent.

Eg: sweet tea or coffee (sugar added to solution)

     bleach (sodium hypochlorite dissolved in water)

HOPE IT HELPS :)

3 0
3 years ago
URGENT!! I will have brainliest!!!
Vlad [161]

Answer:

sorry idk

Explanation:

3 0
3 years ago
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