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3 years ago

Describe at least two advantages and two disadvantages of using wind as a source of energy.

Chemistry

2 answers:

JulijaS [17]3 years ago

8 0

Answer:

1) being a renewable source of energy hence it can be reused and it is not easily depleted.

2) it does not lead to any form of environmental pollution.

1) A large expanse of land is required in order to generate a meaningful quantity of energy.

2) The occurrence of wind is inconsistent hence generation of energy is not steady.

Explanation:

mihalych1998 [28]3 years ago

4 0

Answer:

See Explanation

Explanation:

Wind is a renewable source of energy widely used as a source of energy in order to minimize the pollution that results from some other sources of non renewable energy.

Wind energy has the advantage of;

1) being a renewable source of energy hence it can be reused and it is not easily depleted.

2) it does not lead to any form of environmental pollution.

On the other hand, a lot of space is required in order to mount as many windmills as possible in order to generate enough electricity to serve a large area. Thus, the disadvantages of wind energy are;

1) A large expanse of land is required in order to generate a meaningful quantity of energy.

2) The occurrence of wind is inconsistent hence generation of energy is not steady.

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A bomb calorimeter has a heat capacity of 675 J/°C and contains 925 g of water. If the combustion of 0.500 mole of a hydrocarbon

ikadub [295]

Answer: The enthalpy of the reaction is 269.4 kJ/mol

Explanation:

To calculate the heat absorbed by the calorimeter, we use the equation:

$q_1=c\Delta T$

where,

q = heat absorbed

c = heat capacity of calorimeter = 675 J/°C

$\Delta T$ = change in temperature = $T_2-T_1=(53.88-24.26)^oC=29.62^oC$

Putting values in above equation, we get:

$q_1=675J/^oC\times 29.62^oC=19993.5J$

To calculate the heat absorbed by water, we use the equation:

$q_2=mc\Delta T$

where,

q = heat absorbed

m = mass of water = 925 g

c = heat capacity of water = 4.186 J/g°C

$\Delta T$ = change in temperature = $T_2-T_1=(53.88-24.26)^oC=29.62^oC$

Putting values in above equation, we get:

$q_2=925g\times 4.186J/g^oC\times 29.62^oC=114690.12J$

Total heat absorbed = $q_1+q_2$

Total heat absorbed = $[19993.5+114690.12]J=134683.62J=134.7kJ$

To calculate the enthalpy change of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

q = amount of heat absorbed = 134.7 kJ

n = number of moles of hydrocarbon = 0.500 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction

Putting values in above equation, we get:

$\Delta H_{rxn}=\frac{134.7kJ}{0.500mol}=269.4kJ/mol$

Hence, the enthalpy of the reaction is 269.4 kJ/mol

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3 years ago

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100.-gram sample of H2O() at 22.0°C absorbs 8360 joules of heat. What will be the final temperature of the water?

nexus9112 [7]

_Award brainliest if helped!
Assume Specific Heat capacity of water = 4.186 J/g°C
100g sample,
Q=mcΔθ
8360=100(4.186)(Final Temp.-22.0)
Final Temperature ≈41.97°C

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3 years ago

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How are biotic factors different from abiotic factors in an environment?

exis [7]

Answer:

Explanation:

Biotic factors are alive. Some examples include plants, animals and fungi.

The “a” in front of abiotic will negate the meaning of the word. Therefore, abiotic means not living. Some examples are rocks, water and air.

So, we know that biotic factors are living, and abiotic factors are not living. Therefore, B is correct.

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3 years ago

The blank which are represented by a single uppercase letter,or represented by an uppercase letter followed by a lowercase lette

melomori [17]

Answer: I believe it’s element symbols

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5. A 180 mL disinfectant solution contains 85 mL of isopropyl alcohol. Determine the V/V

lyudmila [28]

The % V/V concentration of a 180-mL disinfectant solution containing 85 mL of isopropyl alcohol is 47 % V/V.

<h3>What is the % V/V concentration?</h3>

It refers to the milliliters of solute for every 100 milliliters of solution.

We have 180 mL of a disinfectant solution that contains 85 mL of isopropyl alcohol (solute).

The % V/V concentration of this solution is:

% V/V = (mL solute/mL solution) × 100% =

% V/V = (85 mL/180 mL) × 100% = 47% V/V

Learn more about % V/V here: brainly.com/question/17055828

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