Answer:
6.57 m/s
Explanation:
First use Hook's Law to determine the F the compressed spring acts on the mass. Hook's Law F=kx; F=force, k=stiffnes of spring (or spring constant), x=displacement
F=kx; F=180(.3) = 54 N
Next from Newton's second law find the acceleration of the mass.
Newton's .2nd law F=ma; a=F/m ; a=54/.75 = 72m/s²
Now use the kinematic equation for velocity (or speed)
v₂²= v₀² + 2a(x₂-x₀); v₂=final velocity; v₀=initial velocity; a=acceleration; x₂=final displacement; x₀=initial displacment.
v₀=0, since the mass is at rest before we release it
a=72 m/s² (from above)
x₀=0 as the start position already compressed
x₂=0.3m (this puts the spring back to it's natural length)
v₂²= 0 + 2(72)(0.3) = 43.2 m²/s²
v₂= = 6.57 m/s
Answer:
Density of unknown material = 3.86 g/cm³
Explanation:
Mass of unknown material, M = 54 gm
The object occupied 14 gm of water.
Volume of unknown material = Volume of 14 gm of water.
Density of water = 1 gm/cm³
Volume of 14 gm of water
Volume of unknown material, V = Volume of 14 gm of water = 14 cm³
Density of unknown material
Answer:
107.3 m/s
Explanation:
The motion of Garlit is a uniformly accelerated motion (=constant acceleration), therefore we can use the following suvat equation:
where
u is the initial velocity
v is the final velocity
a is the acceleration
t is the time
In this problem, we have:
u = 0 (Garlit starts from rest)
is the acceleration
Therefore, the final velocity after t = 6.5 s is:
Answer:
so a man counts 6 waves on a pound in 10 second
Explanation:
6×10 = 60
60/40
so the answer is3
To answer your question it is true