Question

The number of typing errors on a page follows a Poisson distribution with a mean of 6.3. Find the probability of having exactly six (6) errors on a page.

Answer 1

Answer: 0.1595

Step-by-step explanation:

Poisson Distribution Formula

$P(\mathrm{X}=x)=\dfrac{\lambda^{x} e^{-\lambda}}{x !} \\\text{ where } x=0,1,2,3, \ldots \\\\ \lambda= mean number of occurrences in the interval\\\\ e= Euler's constant \approx 2.71828$

Here, $\lambda= 6.3$

x= 6

$P(X=6)=\frac{6.3^6e^{-6.3}}{6!}$

$\approx0.1595$

Hence, the probability of having exactly six (6) errors on a page = 0.1595