2 years ago

What is the nth term of the quadratic sequence 3 11 24 45

Mathematics

1 answer:

Anna71 [15]2 years ago

3 0

9514 1404 393

Answer:

$a_n=\dfrac{1}{2}n^3-\dfrac{1}{2}n^2+6n-3$

Step-by-step explanation:

The first differences are 8, 13, 21. The second differences are 5, 8. The second differences are not constant, so this is <em>not a quadratic sequence</em>.

If we assume it is a cubic sequence, a calculator tells us the formula is ...

$a_n=\dfrac{1}{2}n^3-\dfrac{1}{2}n^2+6n-3$

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