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Snowcat [4.5K]
3 years ago
15

Calculate the molarity of the following solution. 45.7 g C10H12 in 5230 mL of solution unit:

Chemistry
1 answer:
Vladimir [108]3 years ago
4 0

Answer:

Molarity = Moles of solute/Volume of solution(in Litres)

Solute = C10H12

moles of solute = Mass/Molar Mass

Molar Mass of C10H12 = 10(12) + 12(1)

= 132gmol-¹

Mole = 45.7/132 = 0.346mol

Molarity = 0.346/5.23

=0.066M

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Will give brainliest! if 32.0 g of hcl is to be diluted to make a 4.80 m solution, how much water should be added?
nadezda [96]

The required volume of water is 0.18 liters.

<h3>What is molarity?</h3>

Molarity of any solution is define as the number of moles of solute present in per liter of solution as;

M = n/V

Moles of solute will be calculated as:

n = W/M, where

W = given mass of HCl = 32g

M = molar mass of HCl = 36.4g/mol

n = 32 / 36.4 = 0.88 mole

Given molarity of solution = 4.80M

On putting all values in the above equation, we get

V = (0.88) / (36.4) = 0.18 L

Hence required volume of water is 0.18L.

To know more about volume & concentration, visit the below link:

brainly.com/question/26762947

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1 year ago
Write the balanced neutralization reaction that occurs between h2so4 and koh in aqueous solution. Phases are optional.
Nutka1998 [239]

Answer:

The answer to your question is below

Explanation:

H₂SO₄ = sulphuric acid

KOH = potassium hydroxide

This is a neutralization reaction

                       H₂SO₄   +  2 KOH   ⇒     K₂SO₄   +  2H₂O

                                 2 -----------   K  ----------- 2

                                 1 -----------   S  ----------  1

                                 4 ----------   H  ---------   4

                                6 ------------   O ----------  6

4 0
2 years ago
Which planet is the largest?
Alexeev081 [22]

Answer:

1. Jupiter

2. Mercury

3. Venus

4. Venus

5. Jupiter

6. Neptune

7. Mercury

8. Saturn (used to be Jupiter)

4 0
2 years ago
I will mark brainliest if you are correct
alexgriva [62]

Answer:

The right answer to this is (b)

3 0
2 years ago
Read 2 more answers
At 600. K how many moles of gas are in a 1.00 L cylinder at atmospheric pressure?
Anton [14]

Answer:

0.02moles

Explanation:

To answer this question, the general gas law equation is used. The General gas law is:

Pv = nRT

Where; P = standard atmospheric pressure (1 atm)

V = volume (L)

n = number of moles

R = Gas law constant

T = Temperature

For this question; volume = 1.00L, atmospheric pressure (P) = 1 atm, R = 0.0821 L-atm / mol K, T = 600K, n = ?

Therefore; Pv = nRT

n = PV/RT

n = 1 × 1/ 0.0821 × 600

n = 1/49.26

n = 0.0203moles

Hence, there are 0.02 moles of gas.

8 0
3 years ago
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